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irakobra [83]
3 years ago
14

can someone describe how someone is moving-- have examples of positive velocity negative velocity and acceleration and the perso

n being at rest. Can someone help me asap i need Help!! making it into a story
Physics
1 answer:
Rama09 [41]3 years ago
4 0

Assume the motion when you are in the car or in the school bus to go to the school.


To describe the motion the first thing you need is a point of reference. Assume this is your house.


This should be a description:

  • When you are sitting and the car has not started to move you are at rest.
  • The car starts moving from rest, gaining speed, accelerating. You start to move away from your house, with a positive velocity (from you house to your school) and positive acceleration (velocity increases).
  • The car reaches a limit speed of 40mph, and then moves at constant speed. The motion is uniform, the velocity is constant, positive, since you move in the same direction), and the acceleration is zero.
  • When the car approaches the school, the driver starts to slow down. Then, you speed is lower but yet the velocity is positive, as you are going in the same direction. The acceleration is negative because it is in the opposite direction of the motion.
  • When the car stops, you are again at rest: zero velocity and zero acceleration.
  • In all the path your velocity was positive, constant at times (zero acceleration) and variable at others (accelerating or decelerating).
  • When you comeback home, then you can start to compute negative velocities, as you will be decreasing the distance from your point of reference (your house).


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Answer:

x=22.65m

Explanation:

We have an uniformly accelerated motion, with a negative acceleration. Thus, we use the kinematic equations to calculate the distance will it take to bring the car to a stop:

v_f^2=v_0^2-2ax\\\frac{0^2-v_0^2}{-2a}=x\\x=\frac{v_0^2}{2a}

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Recall that the maximum force of friction is defined as F_f=\mu N. So, replacing this:

\mu N=ma\\\mu mg=ma\\a=\mu g\\a=0.901(9.8\frac{m}{s^2})\\a=8.83\frac{m}{s^2}

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<h3>♫ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ♫</h3>

➷ Use this equation:

Q = IT

Rearrange for I

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Substitute in the values:

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<h3><u>✽</u></h3>

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