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irakobra [83]
3 years ago
14

can someone describe how someone is moving-- have examples of positive velocity negative velocity and acceleration and the perso

n being at rest. Can someone help me asap i need Help!! making it into a story
Physics
1 answer:
Rama09 [41]3 years ago
4 0

Assume the motion when you are in the car or in the school bus to go to the school.


To describe the motion the first thing you need is a point of reference. Assume this is your house.


This should be a description:

  • When you are sitting and the car has not started to move you are at rest.
  • The car starts moving from rest, gaining speed, accelerating. You start to move away from your house, with a positive velocity (from you house to your school) and positive acceleration (velocity increases).
  • The car reaches a limit speed of 40mph, and then moves at constant speed. The motion is uniform, the velocity is constant, positive, since you move in the same direction), and the acceleration is zero.
  • When the car approaches the school, the driver starts to slow down. Then, you speed is lower but yet the velocity is positive, as you are going in the same direction. The acceleration is negative because it is in the opposite direction of the motion.
  • When the car stops, you are again at rest: zero velocity and zero acceleration.
  • In all the path your velocity was positive, constant at times (zero acceleration) and variable at others (accelerating or decelerating).
  • When you comeback home, then you can start to compute negative velocities, as you will be decreasing the distance from your point of reference (your house).


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Katarina [22]
I don’t understand the question
3 0
3 years ago
The state of strain at a point is plane strain with εx = ε0, εy = –2ε0, γxy = 0, where ε0 is a positive constant. What is the no
Marat540 [252]

Answer:

The normal strain along an axis oriented 45° from the positive x axis in the clockwise direction is -ε₀/2

Explanation:

Given that

\epsilon_{x}=\epsilon_{o}\\\\\epsilon_{y}=-2\epsilon_{o}\\\\\gamma_{xy}=0\\\\\theta=-45^{o}\\\\\epsilon_{x_{1}}=?

From equation of normal strain in x direction:

\epsilon_{x_{1}}=\epsilon_{x}cos^{2}\theta+\epsilon_{y}sin^{2}\theta+\gamma_{xy{ sin\theta cos\theta

Substituting the values:

\epsilon_{x_{1}}=\epsilon_{o}cos^{2}(-45)-2\epsilon_{o}sin^{2}(-45)+0\\\\\epsilon_{x_{1}}=\frac{\epsilon_{o}}{2}-2\frac{\epsilon_{o}}{2}\\\\\epsilon_{x_{1}}=-\frac{\epsilon_{o}}{2}

6 0
3 years ago
The Outlaw Run roller coaster in Branson, Missouri, features a track that is inclined at 84 ∘ below the horizontal and that span
harina [27]

Answer:

Explanation:

a)

Ff = μmgcosθ

Ff = 0.28(1600)(9.8)cos(-84)

Ff = 458.9217...

Ff = 460 N

b)  ignoring the curves required at top and bottom which change the friction force significantly, especially at the bottom where centripetal acceleration will greatly increase normal forces and thus friction force.

W = Ffd

W = 458.9217(-49.4/sin(-84)

W = 22,795.6119...

W = 23 kJ

c) same assumptions as part b

The change in potential energy minus the work of friction will be kinetic energy.

KE = PE - W

½mv² = mgh - (μmgcosθ)d

v² = 2(gh - (μgcosθ)(h/sinθ))

v = √(2gh(1 - μcotθ))

v = √(2(9.8)(49.4)(1 - 0.28cot84))

v = 30.6552...

v = 31 m/s

5 0
2 years ago
One way to describe a wave crest is the amount of ___________ applied over an area.
Pani-rosa [81]
I believe it’s force but i’m not really sure.
8 0
3 years ago
Read 2 more answers
A 22.0 kg child slides down a slide that makes a 37.0° angle with the horizontal. (a) What is the magnitude of the normal force
patriot [66]

Answer:

(a) 172.185 N

(b) 53^{\circ}

Solution:

As per the question:

Mass of the child, m = 22.0 kg

Angle, \theta = 37.0^{\circ}

Now,

(a) The magnitude of the normal force exerted by the slide on the child:

F_{N} = mgcos\theta

F_{N} = 22\times 9.8cos37^{\circ} = 172.185\ N

Now,

(b) The angle from the horizontal at which the force is directed is:

90^{\circ} - 37^{\circ} = 53^{\circ}

6 0
3 years ago
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