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irakobra [83]
3 years ago
14

can someone describe how someone is moving-- have examples of positive velocity negative velocity and acceleration and the perso

n being at rest. Can someone help me asap i need Help!! making it into a story
Physics
1 answer:
Rama09 [41]3 years ago
4 0

Assume the motion when you are in the car or in the school bus to go to the school.


To describe the motion the first thing you need is a point of reference. Assume this is your house.


This should be a description:

  • When you are sitting and the car has not started to move you are at rest.
  • The car starts moving from rest, gaining speed, accelerating. You start to move away from your house, with a positive velocity (from you house to your school) and positive acceleration (velocity increases).
  • The car reaches a limit speed of 40mph, and then moves at constant speed. The motion is uniform, the velocity is constant, positive, since you move in the same direction), and the acceleration is zero.
  • When the car approaches the school, the driver starts to slow down. Then, you speed is lower but yet the velocity is positive, as you are going in the same direction. The acceleration is negative because it is in the opposite direction of the motion.
  • When the car stops, you are again at rest: zero velocity and zero acceleration.
  • In all the path your velocity was positive, constant at times (zero acceleration) and variable at others (accelerating or decelerating).
  • When you comeback home, then you can start to compute negative velocities, as you will be decreasing the distance from your point of reference (your house).


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Katyanochek1 [597]

<u>Answer:</u> The energy released in the given nuclear reaction is 3.526 MeV.

<u>Explanation:</u>

For the given nuclear reaction:

_{19}^{42}\textrm{K}\rightarrow _{20}^{42}\textrm{Ca}+_{-1}^{0}\textrm{e}

We are given:

Mass of _{19}^{42}\textrm{K} = 41.962403 u

Mass of _{20}^{42}\textrm{Ca} = 41.958618 u

To calculate the mass defect, we use the equation:

\Delta m=\text{Mass of reactants}-\text{Mass of products}

Putting values in above equation, we get:

\Delta m=(41.962403-41.958618)=0.003785u

To calculate the energy released, we use the equation:

E=\Delta mc^2\\E=(0.003785u)\times c^2

E=(0.003785u)\times (931.5MeV) (Conversion factor: 1u=931.5MeV/c^2 )

E=3.526MeV

Hence, the energy released in the given nuclear reaction is 3.526 MeV.

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3 years ago
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zmey [24]
Evolution should be the answer
5 0
3 years ago
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You’re speeding at 85 km/hr when you notice that you’re only 10 m behind the car in front of you,
solmaris [256]
Your position in meters will, measured relative to the starting point of the car behind you, be 
x1(t) = 10 + 23.61 t - 1/2 4.2 t^2 
his position will be 
x2(t) = 16.67 t 
Hence at any time the separation s(t) will be 
s(t) = x1(t) - x2(t) = 10 + 6.94 t -2.1 t^2 
Now I assume you mean that you will decelerate UNTIl you are driving at the legal speed limit (60 km/h). That will take you: 
16.67 m/s = 23.61m/s - 4.2 m/s^2 * t 
t = 1.65 seconds 
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s(1.65) = 10 + 6.94 *1.65 -2.1 (1.65)^2 = 15.73 meters. 
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3 years ago
HELP ASAP TIMER
devlian [24]

Answer:

b  Use a balance to determine the mass of the car. Use a motion sensor to measure the speed of the car at a time of 0s and at time of 5s .

Explanation:

The right way to measure the net force on the car is take the measurement of its mass then find the speed of the car within the time 0s to 5s.

This is because the net force acting on car is given as;

   Force  = mass x acceleration

By using the balance, the mass is determine

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v is the final velocity

u is the initial velocity

t is the time taken

  Now,

         Force  = mass x  \frac{v - u}{t}  

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JulijaS [17]

Answer:

it's very easy and simple answer u can't do it

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