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Bumek [7]
2 years ago
5

Which of the following would be their unit of acceleration?

Physics
2 answers:
kumpel [21]2 years ago
5 0

Answer:

Unit of acceleration is the metre per second per second (m/s2).

Explanation:

I AM NOT FREAKING SURE

VladimirAG [237]2 years ago
4 0
Meters per second squared or m/s2
Crown please
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A baseball weighing 0.5 kg falls from the sky. You hit it with a bat with a force of 50 N at an upward angle of 45°.
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During which time does Jamal have the greatest momentum?
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An astronaut 100m from the spaceship observes a 200kg meteoroid that drifts toward the shop at 10m/sec. If the astronaut can gai
Fynjy0 [20]

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8 0
3 years ago
A mass M suspended by a spring with force constant k has aperiod T when set into oscillations on Earth. Its period on Mars,whose
olchik [2.2K]

Answer:

C)T

Explanation:

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3 years ago
In pairs figure-skating competition, a 65-kg man and his 45-kg female partner stand facing each other both at rest on the ice. I
Lina20 [59]

Answer:

The final velocity of her partner is approximately -1.04 m/s or 1.04 m/s in the opposite direction to her direction of motion

Explanation:

The given parameters are;

The mass of the man, m₁ = 65 kg

The mass of the woman, m₂ = 45 kg

Taking the relative initial velocity of the man and the woman as 0 m/s, we have;

The initial velocity of the man, v₁₁ = 0 m/s

The initial velocity of the man, v₁₂ = 0 m/s

The final velocity of the woman, v₂₂ = 1.5 m/s

The final velocity of the man = v₂₁

Therefore, we have, by the conservation of momentum principle;

The total initial momentum = The total final momentum

Which gives;

m₁ × v₁₁ + m₂ × v₁₂ = m₁ × v₂₁ + m₂ × v₂₂

Substituting the known values;

65 × 0 + 45 × 0 = 65 × v₂₁ + 45 × 1.5

∴ 65 × v₂₁ + 45 × 1.5 = 0

45 × 1.5 = - 65 × v₂₁

v₂₁ = 45 × 1.5/(-65) ≈ -1.04 m/s

The final velocity of the man, her partner = v₂₁ ≈ -1.04 m/s.

6 0
2 years ago
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