Answer:
New location at time 3.01 is given by: (7.49, 2.11)
Explanation:
Let's start by understanding what is the particle's velocity (in component form) in that velocity field at time 3:
![V_x=x^2=7^2=49\\V_y=x+y^2=7+2^2=11](https://tex.z-dn.net/?f=V_x%3Dx%5E2%3D7%5E2%3D49%5C%5CV_y%3Dx%2By%5E2%3D7%2B2%5E2%3D11)
With such velocities in the x direction and in the y-direction respectively, we can find the displacement in x and y at a time 0.01 units later by using the formula:
![distance=v\,*\, t](https://tex.z-dn.net/?f=distance%3Dv%5C%2C%2A%5C%2C%20t)
![distance_x=49\,(0.01)=0.49\\distance_y=11\,(0.01)=0.11](https://tex.z-dn.net/?f=distance_x%3D49%5C%2C%280.01%29%3D0.49%5C%5Cdistance_y%3D11%5C%2C%280.01%29%3D0.11)
Therefore, adding these displacements in component form to the original particle's position, we get:
New position: (7 + 0.49, 2 + 0.11) = (7.49, 2.11)
D all of them is the answer. All three can be used to celebrate sporting events
Temperature is the average kinetic energy of an object