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2 years ago

In the reaction MnO₂ + 4HCI MnCl₂ + 2H₂O + Cl₂, which species is reduced?

Chemistry

2 answers:

Triss [41]2 years ago

6 0

Answer:

4 HCl (aq) + MnO2 (s) → MnCl2 (aq) + Cl2 (g) + 2 H2O (l)

This is an oxidation-reduction (redox) reaction:

MnIV + 2 e- → MnII (reduction)

2 Cl-I - 2 e- → 2 Cl0 (oxidation)

MnO2 is an oxidizing agent, HCl is a reducing agent.

Reactants:

HCl – Chlorane, Hydrogen chloride

Other names: Hydrochloric acid
Appearance: Colorless, transparent liquid, fumes in air if concentrated; Colorless gas; Colourless compressed liquefied gas with pungent odour; Colorless to slightly yellow gas with a pungent, irritating odor. [Note: Shipped as a liquefied compressed gas.]

MnO2 – Manganese oxide, Manganese(IV) oxide

Other names: Manganese dioxide, Pyrolusite, Hyperoxide of manganese

Appearance: Brown-black solid Black-to-brown powder

Products:

MnCl2 – Manganese(II) chloride, Manganese dichloride

Other names: Manganous chloride, Manganous dichloride Manganese(II) chloride (1:2)

Appearance: Pink solid (tetrahydrate)

Cl2

Names: Chlorine, Molecular chlorine

Appearance: Greenish-yellow compressed liquefied gas with pungent odour ; Greenish-yellow gas with a pungent, irritating odor. [Note: Shipped as a liquefied compressed gas.]

H2O – Water, oxidane

Other names: Water (H2O) Hydrogen hydroxide (HH or HOH) Hydrogen oxide

Appearance: White crystalline solid, almost colorless liquid with a hint of blue, colorless gas

Explanation:

Igoryamba2 years ago

3 0

Answer:

4 HCl (aq) + MnO2 (s) → MnCl2 (aq) + Cl2 (g) + 2 H2O (l)

This is an oxidation-reduction (redox) reaction

Explanation:

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3 years ago

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3 years ago

Find the grams in 1.26*10^-4 mol of HC2H3O2

Oksana_A [137]

Answer:

0.00757 grams

Explanation:

Find the molar mass of the compound: which is 60.05.

The molar mass is basically just the sum of all the atomic masses of each of the elements.

Then multiply the molar mass by the number of moles in the compound, which is 1.26 x 10^-4 moles.

Your answer should be 0.00757 grams.

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3 years ago

5. What are the relative rates of diffusion for methane, CH, and oxygen, O2? If O2 la travels 1.00 m in a certain amount of time

11Alexandr11 [23.1K]

Answer:

The relative rates of diffusion for methane and oxygen is 1.4142.

Methane gas will be able to travel 1.4142 meter in the same conditions.

Explanation:

To calculate the rate of diffusion of gas, we use Graham's Law.

This law states that the rate of effusion or diffusion of gas is inversely proportional to the square root of the molar mass of the gas. Mathematically written as:

$\text{Rate of diffusion}\propto \frac{1}{\sqrt{\text{Molar mass of the gas}}}$