Answer:
0.085 moles of N₂O₅ are needed
Explanation:
Given data:
Mass of NO₂ produces = 7.90 g
Moles of N₂O₅ needed = ?
Solution:
2N₂O₅ → 4NO₂ + O₂
Number of moles of NO₂ produced :
Number of moles = mass/ molar mass
Number of moles = 7.90 g/ 46 g/mol
Number of moles = 0.17 mol
now we will compare the moles of NO₂ with N₂O₅.
NO₂ : N₂O₅
4 : 2
0.17 : 2/4×0.17 = 0.085 mol
Thus, 0.085 moles of N₂O₅ are needed.
Answer:
FCI=88.0818 MM≅88 MM
Explanation:
Empirical correlation based on the work of Bridgwater and Mumford (1979):
For Liquid or solid phase Plants:
F<60,000 tonne/yr Eq (1)
F≥60,000 tonnes/yr Eq (2)
Where:
N is the number of functional units
F is the process throughput tonnes/yr
In our case F=40,000 tonne/yr <60,000 tonne/yr, We are going to use Eq (1)
F<60,000 tonne/yr
N=8, F=40,000 tonne/yr
FCI=88.0818 MM≅88 MM
Answer:
It indicates that the ratio of the particles in the composition of the sample will always be 2:1 with Hydrogen: Sulfur
Answer:
Ethylene oxide
Explanation:
Ethylene oxide is an organic compound with the formula C2H4O. It is a cyclic either and the simplest epoxied: a three-membraned ring consisting of one oxygen atom and two carbon atoms!
