If HA, an acid, is 15 percent dissociated in a 2.00 molar solution, what is the Ka for the solution? A. 5.3 × 10-2 B. 6.4 × 10-3
C. 1.1 × 10-2 D. 1.2 × 10-2
1 answer:
Answer: 0.3
Explanation:
We know that
Ka = [H+] * [A-] / [HA]
And the acid is 15 % dissociated means that
[A-] / [HA] *100 = 15%
So
[A-] / [HA] = 0.15
Then we know that [H+] = [A-] = 2 molar
Replacing we have
Ka = 2 molar * 0.15 = 0.3
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