The density : 1.96 g/L
<h3>Further explanation</h3>
Ideal gas Law
Pv=nRT
where
P = pressure, atm , N/m²
V = volume, liter
n = number of moles
R = gas constant = 0.082 l.atm / mol K (P= atm, v= liter),or 8,314 J/mol K (P=Pa or N/m², v= m³)
T = temperature, Kelvin
so for density,
MW CO₂ = 44 g/mol

Answer:
The answer to your question is 245.9 g of Fe₂O₃
Explanation:
Data
grams of Fe₂O₃ = ?
grams of Fe = 172 g
Balanced chemical reaction
Fe₂O₃ + 3H₂ ⇒ 2Fe + 3H₂O
Process
1.- Calculate the molar mass of of Iron Oxide and Iron
Fe₂O₃ = (2 x 56) + (3 x 16) = 112 + 48 = 160 g
2Fe = 2 x 56 = 112 g
2.- Use proportions and cross multiplication to solve this problem
160 g of Fe₂O₃ --------------- 112 g of Fe
x ---------------- 172 g of Fe
x = (172 x 160)/112
x = 27520/112
x = 245.9 g of Fe₂O₃
Electronegativity decreases as you go down a colum in the periodic table.
The specific heat capacity of the given substance is -0.66 J/g°C.
<u>Explanation:</u>
The heat absorbed by any substance is the product of its mass, specific heat capacity and change in temperature.
q = m × c × ΔT
m is the mass in grams
q = amount of heat released or absorbed in J
ΔT = change in temperature in °C = 5 -50 = -45°C
c = specific heat capacity in J/g°C
c = 
Plugin the values, we will get,
c = 
= -0.66 J/g°C
That would be 58.6 oxide because if the 41.2 plus the oxide would be 48 plus the other particcles inside it so it equaled 58.6 oxide