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nikklg [1K]
3 years ago
7

Does 21.6,28.8,36 equal a right triangle

Mathematics
1 answer:
Alex_Xolod [135]3 years ago
3 0
21.6 < 28.8 < 36

<span>if they are the lengths of the sides of a right triangle then:

21.6^2+28.8^2=36^2\\\\L_s=466.56+829.44=1296\\\\R_s=1296\\\\L_s=R_s

therefore it's the right triangle.</span>

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Find the equation of the line<br> In the form y=mx+b
Aleonysh [2.5K]

Answer:

y = -1/3x + 5

Step-by-step explanation:

-1/3 is the slope because the line goes down 1 unit and right 3 units.

The y-intercept is 5 because that is where the line crosses the y-axis.

8 0
3 years ago
What is a cubic polynomial function with zeros 3,3 and -3? show your work.​
Brums [2.3K]

Answer:

Cubic polynomial function with zeros 3,3 and -3 is \mathbf{x^3-3x^2-9x+27=0}

Step-by-step explanation:

We need to find a cubic polynomial function with zeros 3,3 and -3.

If zeros of polynomial are: 3,3,and -3

we can write:

x=3, x=3, x=-3

Or

We can write:

x-3=0, x-3=0, x+3=0

Now, we can write them as:

(x-3)(x-3)(x+3)=0

Multiplying the terms, we can find the polynomial:

(x-3)(x-3)(x+3)=0\\(x(x-3)-3(x-3))(x+3)=0\\(x^2-3x-3x+9)(x+3)=0\\(x^2-6x+9)(x+3)=0\\x(x^2-6x+9)+3(x^2-6x+9)=0\\x^3-6x^2+9x+3x^2-18x+27=0\\x^3-6x^2+3x^2+9x-18x+27=0\\x^3-3x^2-9x+27=0

So, cubic polynomial function with zeros 3,3 and -3 is \mathbf{x^3-3x^2-9x+27=0}

4 0
3 years ago
At the moment a hot cake is put in a cooler, the difference between the cake's and the cooler's temperatures is 50\degree50°50,
Len [333]

Answer:

D(t)=50\cdot (0.8)^{t}

Step-by-step explanation:

The equation for exponential decay function is given as:

D(t)=a(1-r)^{t}

where:

D(t)= difference in temperature t=time

r=rate of change

a =initial value of the temperature

From the given problem:

Initial Temperature,a=50°C

Rate of Decay,r=\frac{1}{5}

Therefore the function for the difference in temperature is given as:

D(t)=50(1-\frac{1}{5})^{t}

D(t)=50\cdot (\frac{4}{5})^{t}

We can convert \frac{4}{5} to decimal and write the function as:

D(t)=50\cdot (0.8)^{t}

7 0
3 years ago
Read 2 more answers
How do I show that this function is one-to-one algebraically?<br> <img src="https://tex.z-dn.net/?f=f%28x%29%3D%20%28x-2%29%5E%7
Gwar [14]
For a one-to-one function, f(x) = f(y).
 So, lets find f(x) and f(y).

We know, 
f(x) = (x - 2)³ + 8

Now,
f(y) = (y - 2)³ + 8

Now, we said earlier, for a function to be one-to-one, f(x) = f(y).

Therefore,

            f(x) = f(y)
(x - 2)³ + 8 = (y - 2)³ + 8
      (x - 2)³ = (y - 2)³     
          x - 2 = y - 2
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Since we got x = y, we know for every x, there is one and only one y. Therefore, the function is one-to-one function.
 
6 0
3 years ago
Use the information in the diagram to determine the height of the tree
Fantom [35]
The height of the tree is 75
8 0
3 years ago
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