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STALIN [3.7K]
3 years ago
14

Which law states that for any closed loop, the sum of the length segments times the magnetic field in the direction of the segme

nt is proportional to the electric current enclosed in the loop?
A. Ohm’s Law
B. Faraday’s Law
C. Ampere’s Law
D. Gauss’ Law
E. Edison’s Law
Physics
2 answers:
vovangra [49]3 years ago
8 0

Answer:

Ampere's law

Explanation:

As per Ampere Law we know that line integral of magnetic field along the closed ampere loop is equal to the product of permeability of the medium with total enclosed current in that ampere's loop

so it is given as

\int B.dL = \mu_0 I_{enclosed}

so here we can say that correct answer for the given condition is Ampere's law

dedylja [7]3 years ago
3 0
That's Ampere's Law.  ( C ).
The magnetic permeability is the proportionality constant.
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Answer:

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Explanation:

The answer is true.

Balance forces acting on a body will not change the motion of the body because the body experiences no net resultant force in one direction. When any body experiences equal forces with opposite directions, the net force or the resultant force experience by the body is zero.

In case of an unbalanced forces, there is a net force acting in one direction and so it causes the body to change in its state of motion in the direction of the net force.

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2 years ago
A car is moving 14.4 m/s. It decelerates at -1.55 m/s^2 for 4.26 s. It then accelerates at 1.83 m/s^2 until it reaches 11.8 m/s.
Aleonysh [2.5K]

The total time is 6.45 s

Explanation:

The motion of the car is a uniformly accelerated motion, so we can use suvat equations.

In the first part,

u_1 = 14.4 m/s (initial velocity)

a_1 = -1.55 m/s^2 (acceleration)

t_1=4.26 s (time of the first part)

So, we can find the velocity of the car after the first part, by using

v_1 = u_1 +a_1 t_1 =14.4+(-1.55)(4.26)=7.8 m/s

This is therefore the initial velocity of the second part:

u_2 = v_1 = 7.8 m/s

a_2 = 1.83 m/s^2 (acceleration in the second part)

v_2 = 11.8 m/s (final velocity)

And therefore,

v_2 = u_2 + a_2 t_2\\t_2=\frac{v_2-u_2}{a_2}=\frac{11.8-7.8}{1.83}=2.19 s

So, the total time is

t=t_1+t_2=4.26+2.19=6.45 s

Learn more about uniformly accelerated motion:

brainly.com/question/9527152

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#LearnwithBrainly

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