Part a)
As we know that energy stored inside the capacitor is given as

for a given capacitor we know

Now we can use it in above equation to find the energy



PART b)
If two negative charges are hold near to each other and then released
Then due to mutual repulsion they start moving away from each other
Due to mutual repulsion as the two charges moving away the electrostatic potential energy of two charges will convert into kinetic energy of the two charges.
So here as they move apart kinetic energy will increase while potential energy will decrease
Part c)
As we know that capacitance is given as

here we know that




here the charge density of metal plate is given as

now the electric field is given Gauss law

now here E = constant
so we will have

Since total area on both sides of plate will be double and becomes 2A



Now if we will find the electric field inside the metal plate
Then as we know that total charge inside the plate will always be zero
so we have

Explanation:
Contact force is any force that requires contact. An object that exerts a force on another object by touching it is exerting a contact force. Examples of contact force are friction and normal force.
Examples of a non-contact force are gravity and magnetism.
Answer:
a)

b)

Explanation:
L = inductance of the Inductor = 3.14 mH = 0.00314 H
C = capacitance of the capacitor = 5.08 x 10⁻⁶ F
a)
f = frequency = 55.7 Hz
Impedance is given as



b)
f = frequency = 11000 Hz
Impedance is given as


