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3 years ago

What is the deBroglie wavelength of an electron moving at 1.37 x 106 m/s if the mass of the electron is 9.11 x 10-28 g

Physics

1 answer:

Nina [5.8K]3 years ago

7 0

Answer:

The value is $\lambda = 5.30 *10^{-10 } \ m$

Explanation:

From the question we are told that

The velocity of the electron is $v = 1.37 *10^{6} \ m/s$

The mass of the electron is $m = 9.11 *10^{-28} \ g = 9.11 *10^{-31} \ kg$

Generally the deBroglie wavelength is mathematically represented as

$\lambda = \frac{h}{mv}$

Here h is the Planck'c constant with value $h = 6.62607015 * 10^{-34} J \cdot s$

$\lambda = \frac{6.62607015 * 10^{-34} }{9.11 *10^{-31} * 1.37 *10^{6}}$

=> $\lambda = 5.30 *10^{-10 } \ m$

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3 years ago

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iogann1982 [59]

Answer:

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3 years ago

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Answer:

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3 years ago

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