Question

What is the deBroglie wavelength of an electron moving at 1.37 x 106 m/s if the mass of the electron is 9.11 x 10-28 g

Answer 1

Answer:

The value  is  $\lambda = 5.30 *10^{-10 } \ m$

Explanation:

From the question we are told that

    The velocity of the electron is  $v = 1.37 *10^{6} \ m/s$

    The mass of the electron is  $m = 9.11 *10^{-28} \ g = 9.11 *10^{-31} \ kg$

Generally the  deBroglie wavelength  is mathematically represented as

       $\lambda = \frac{h}{mv}$

Here h is the Planck'c constant with value  $h = 6.62607015 * 10^{-34} J \cdot s$

So

      $\lambda = \frac{6.62607015 * 10^{-34} }{9.11 *10^{-31} * 1.37 *10^{6}}$

=>   $\lambda = 5.30 *10^{-10 } \ m$