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taurus [48]
4 years ago
11

A student is studying the potential energy change of a 50 kg object raised 110 km above Earth's surface. What will be the percen

tage error if he simply used the approximate relation ΔU = mgΔy? Hint
Physics
1 answer:
Law Incorporation [45]4 years ago
7 0

Answer:

The percentage error is given by 99.9 %

Explanation:

Given:

Mass of object m = 50 kg

Height h = 110 km

From the formula of potential energy,

   U = mgh

Where g = 9.8 \frac{m}{s}

   U = 50\times 9.8 \times 110000

Here true value of potential energy,

   U = 50 \times 9.8 \times 11 \times 10^{4}

Approximate value of student,

   U = 50 \times 9.8 \times 110

Absolute error is given by

    = true value - approximate value

    = 50 \times 9.8 \times 11 \times 10^{4} - 50 \times 9.8 \times 110

    = 53846100

Hence percentage error,

    = \frac{53846100}{50 \times 9.8 \times 11 \times 10^{4} }

    = 0.999 \times 100 %

    = 99.9 %

Therefore, the percentage error is given by 99.9 %

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0.84 m

Explanation:

Given in the y direction:

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5 0
4 years ago
Please Help
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