Assume that the age of Alicia is x and that of Amy is y
Twice the age of Alicia = 27
Eight years older means we will add 8
Therefore, the statement "<span>Amy is eight years older than twice her cousin Alicia’s age" can be represented as follows:
y = 8 + 2x (equation)
The sum of their ages is less than 32 can be represented as:
x + y < 32 which can also be written as y < 32-x (inequality)
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Answer:
A) You would move it 2 times B) The Exponent would be 10^2
Step-by-step explanation:
This one's hard to explain..if you want you can message me about it :)
AB means A X B so you have to do 14 / 9 which is 1.5 or there abouts.
Let P = number of coins of pennies (1 penny = 1 cent)
Let N = number of coins of nickels (1 nickel = 5 cents)
Let D = number of coins of dimes (1 dime = 10 cents)
Let Q = number of coins of quarters (1 quarter = 25 cents)
a) P + N + D + Q = 284 coins, but P = 173 coins, then:
173 + N + D + Q =284 coins
(1) N + D + Q = 111 coins
b) D = N + 5 OR D - N =5 coins
(2) D - N = 5 coins
c) Let's find the VALUE in CENTS of (1) that is N + D + Q = 111 coins
5N + 10D + 25 Q = 2,278 - 173 (1 PENNY)
(3) 5N + 10D + 25Q = 2105 cents
Now we have 3 equation with 3 variables:
(1) N + D + Q = 111 coins
(2) D - N = 5 coins
(3) 5N + 10D + 25Q = 2105 cents
Solving it gives:
17 coins N ( x 5 = 85 cents)
22 coins D ( x 10 = 220 cents)
72 coins D ( x 25 = 1,800 cents)
and 173 P,
proof:
that makes a total of 85+2201800+172 =2,278 c or $22.78
False it is roughly 3.74 so it is less than 5. Becuase
if thats what ur asking lol
