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amid [387]
2 years ago
13

Is ninhydren test positive for protein?

Chemistry
1 answer:
lyudmila [28]2 years ago
5 0
The Ninhydrin test is not effective to detect high molecular weight proteins as the steric hindrance limits the ninhydrin from reaching the α-amino groups.
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The solid form of a substance is usually more dense than its liquid and gaseous forms. Similarly the liquid form is usually more
bonufazy [111]
A is the answer.

Ice is solid, however, water is liquid. Yet ice still floats which is less dense than water.

Hope this helps!
4 0
3 years ago
Which of the following is NOT a way that thermal energy is transferred?
g100num [7]

Answer:

Your answer would be D.) Convection. I hope this helps you! :)

3 0
2 years ago
I need help with these 4
storchak [24]

Rift Valley Examples

  • East African
  • Rhine Rift Valley (Germany)
  • Baikal Rift Valley (Russia)

Rift Valley Facts/Characteristics

  • Bordered by fault zones and separating land masses
  • A portion of land that drops, forming a valley.
  • Formed as tectonic plates move.

Fossils - Examples

  • Bones
  • Shells
  • Exoskeletons
  • Stone imprints of animals.

Non Examples of Fossils

  • Stones
  • rocks
  • Some bones (If they are fossils they will be a lot heavier than other bones.

Hope this helps.

5 0
3 years ago
Write the symbol for every chemical element that has atomic number greater than 55 and atomic mass less than 144.0 u
laila [671]
You will need a periodic table to help you answer this problem. The atomic numbers are arrange from lowest to highest in the periodic table. You can locate element number 55 to be Cesium with an atomic weight of 132.905 amu. So, you start from element 56. The following elements are:

56     Barium       137.328 amu
57     Lanthanium   138.905 amu
58     Cerium       140.116 amu
59     <span>Praseodymium    140.908 amu
60     Neodymium   144.243 amu

Neodymium is already greater than 144 amu. Therefore, these elements only include Barium, Lanthanium, Cerium and Praseodymium.</span>
3 0
2 years ago
If 45.0 mL of ethanol (density =0.789g/mol) initially at 6.0°C mix with 45.0 mL of water (density =1.0 g/mol) initially at 28.0°
Likurg_2 [28]

The final temperature of the mixture : 21.1° C  

<h3>Further explanation  </h3>

The law of conservation of energy can be applied to heat changes, i.e. the heat received / absorbed is the same as the heat released  

Q in(gained) = Q out(lost)  

Heat can be calculated using the formula:  

Q = mc∆T  

Q = heat, J  

m = mass, g  

c = specific heat, joules / g ° C  

∆T = temperature difference, ° C / K  

Q ethanol=Q water

mass ethanol=

\tt mass=\rho\times V\\\\mass=0.789\times 45=35.505~g

mass water =

\tt mass=1~g/ml\times 45~ml=45~g

then the heat transfer :

\tt 35.505\times 2.42~J/g^oC\times (t-6)=45\times 4.18~J/g^oC\times (28-t)\\\\85.922t-515.533=5266.8-188.1t\\\\274.022t=5782.33\rightarrow t=21.1^oC

5 0
2 years ago
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