1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
bezimeni [28]
3 years ago
11

Should someone who lives on the sixth floor of an apartment building be concerned about radon in his or her apartment? Why or wh

y not?
Chemistry
1 answer:
torisob [31]3 years ago
3 0

Answer:

The person should not be concerned about radon.

Explanation:

<em>A person living on the sixth floor of an aparment probably should not be concerned about radon</em>. In the conditions of the Earth's atmosphere (temperature and pressure), radon exists as a gas. This gas has a density that is approximately 8 times higher than the density of air (9.73 g/L compared to 1.22 g/L). <em>This means that radon gas would not rise, and instead remain close to the ground</em>, meaning that an apartment on a sixth floor is too far away from the ground for radon gas to reach there.

A gas being denser than air is also the reason why if you blow into a balloon, it will fall to the ground, because CO₂ is denser than air.

You might be interested in
Which of the following will form a solution? (Select all that apply.)
SSSSS [86.1K]

Answer:

sand and water

Explanation:

when u mix these both it will become like a paste

4 0
2 years ago
If a substance cannot be broken down chemically into a simpler substance what is it
Vikentia [17]

Answer: An Element

Explanation:

An element is a substance that cannot be split into smaller substance. It is made up of one kind of atom and can exist either as molecules  (e.g nitogen) or an atom (e.g argon).

6 0
3 years ago
Read 2 more answers
What are the classes of alkanol
LuckyWell [14K]
1-PRIMARY ALKANOL 2-SECONDARY ALKANOL 3-TERTIARY ALKANOL
8 0
3 years ago
Converting carbon to nitrogen by increasing the number of protons from 6 to 7 and decreasing the number of neutrons from 8 to 7
Anton [14]

this is beta decay as the mass number stays the same but proton number changes, this is specifically beta minus as a neuron changes into a proton
4 0
3 years ago
Read 2 more answers
4. Juan tiene un cilindro de 40 libras herméticamente cerrado con gas propano y lo conecta mediante una válvula a otro cilindro
ch4aika [34]

Answer:

Ver explicacion

Explanation:

Cuando el cilindro de 40 libras está conectado al cilindro de 100 libras, generamos una presión que continúa hasta que los dos cilindros alcanzan la misma presión de gas en equilibrio. Recuerde que el cilindro de 100 libras estaba inicialmente vacío. Esto significa que su presión inicial es 0. El cilindro de 40 libras ya estaba lleno, por lo que dividimos esta cantidad en dos para tener en cuenta su distribución entre los dos cilindros.

Ahora tenemos 20 libras de gas propano presentes en cada cilindro. La implicación de esto es que, en el cilindro de 100 libras, necesitamos 80 libras adicionales para completar las 100 libras.

5 0
2 years ago
Other questions:
  • Написати 6 ізомерів С6Н15N
    9·1 answer
  • Why is the periodic table such as useful tool for chemist?
    5·1 answer
  • - What is the frequency of light whose waveler
    8·1 answer
  • How many atoms are in 2 miles of h2o
    8·1 answer
  • (PLZ HELP ME ON THIS!!!) Which of the following will change if you apply unbalanced forces to an object?
    7·2 answers
  • Which statement about enzymes is true? A. They are large molecules that decrease the rate of reactions in the body. B. They are
    5·2 answers
  • If 10.0 L of oxygen gas at STP are heated to 512 Celsius what will be the new volume of the gas if the pressure is also increase
    5·1 answer
  • Use the balanced equation below to answer the question that follows
    13·1 answer
  • Question 6 (1 point)
    8·1 answer
  • What is skeleton?<br>Write any two function of skeleton .​
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!