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bezimeni [28]
3 years ago
11

Should someone who lives on the sixth floor of an apartment building be concerned about radon in his or her apartment? Why or wh

y not?
Chemistry
1 answer:
torisob [31]3 years ago
3 0

Answer:

The person should not be concerned about radon.

Explanation:

<em>A person living on the sixth floor of an aparment probably should not be concerned about radon</em>. In the conditions of the Earth's atmosphere (temperature and pressure), radon exists as a gas. This gas has a density that is approximately 8 times higher than the density of air (9.73 g/L compared to 1.22 g/L). <em>This means that radon gas would not rise, and instead remain close to the ground</em>, meaning that an apartment on a sixth floor is too far away from the ground for radon gas to reach there.

A gas being denser than air is also the reason why if you blow into a balloon, it will fall to the ground, because CO₂ is denser than air.

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When 6.040 grams of a hydrocarbon, CxHy, were burned in a combustion analysis apparatus, 18.95 grams of CO2 and 7.759 grams of H
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Answer: The empirical formula is CH_2 and molecular formula is C_4H_8

Explanation:

We are given:

Mass of CO_2 = 18.95 g

Mass of H_2O= 7.759 g

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Molar mass of water = 18 g/mol

For calculating the mass of carbon:

In 44g of carbon dioxide, 12 g of carbon is contained.

So, in 18.59 g of carbon dioxide, =\frac{12}{44}\times 18.59=5.07g of carbon will be contained.

For calculating the mass of hydrogen:

In 18g of water, 2 g of hydrogen is contained.

So, in 7.759 g of water, =\frac{2}{18}\times 7.759=0.862g of hydrogen will be contained.

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Mass of H = 0.862 g

Step 1 : convert given masses into moles.

Moles of C =\frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{5.07g}{12g/mole}=0.422moles

Moles of H=\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{0.862g}{1g/mole}=0.862moles

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For C =\frac{0.422}{0.422}=1

For H =\frac{0.862}{0.422}=2

The ratio of C : H = 1: 2

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The molecular weight = 56.1 g/mole

Now we have to calculate the molecular formula.

n=\frac{\text{Molecular weight }}{\text{Equivalent weight}}=\frac{56.1}{14}=4

The molecular formula will be=4\times CH_2=C_4H_8

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