<u>Answer:</u> The products of the reaction will be 
<u>Explanation:</u>
Single displacement reaction is defined as the reaction in which more reactive element displaces a less reactive element from its chemical reaction.
The general chemical equation for the single displacement reaction follows:

The given chemical equation follows:

Bromine element is more reactive than iodine element. Thus, can easily replace iodine from its chemical reaction.
Hence, the products of the reaction will be 
A bowling ball.
definition of dense-closely compacted in substance
4 moles of water are produced
Explanation:
- 4 moles of water are produced when 5 moles of hydrogen is reacted with 2 moles of oxygen gas
- The balanced equation given is when 2 moles of hydrogen reacts with 1 mole of oxygen and it forms 2 moles of water.
- The equation we have to solve is the 5 moles of hydrogen is reacting with 2 moles of oxygen gas, we can write the equation as
- This is the balanced equation when 5 moles of hydrogen reacts with 2 moles of oxygen. The balanced equation means the number of hydrogen atoms and oxygen atoms on both sides would be equal in number.
Direct Proportion and The Straight Line Graph.Straight<span> line graphs that go through the origin, like the one immediately below, show that the quantities on the graph are in direct proportion.
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cbuck763
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So we know that the equation for density is:

where D is the density, m is the mass in grams, and V is the volume in mL.
So since we know two of the variables, mass and density, we can solve for the volume:



Therefore, the volume of this urine sample is 144.12mL.