Before addition of HCl,
conc. of CH3COOH = 0.450 M
conc. of CH3COONa = 0.550 M
After addition of 0.08 M HCl, following reaction occurs in system:
HCl + CH3COONa ↔ CH3COOH + NaCl
Thus, in reaction system conc. of CH3COOH will increase to 0.53 M (0.08M + 0.450M)
And, conc to CH3COONa will reduce to 0.47 M (0.550M - 0.08M)
Now, conc. of H+ ions = ka
![\frac{[acid]}{[conjugated base]}](https://tex.z-dn.net/?f=%20%5Cfrac%7B%5Bacid%5D%7D%7B%5Bconjugated%20base%5D%7D)
where ka = dissociation constant for acid = 10^-5 for Ch3COOH
∴ conc. of H+ ions =
= 1.1277 x 10^-5
Now, pH = -log [H+] = -log (1.1227 x 10^-5) = 4.94
Answer:
0.100 M AlCl₃
Explanation:
The variation of boiling point by the addition of a nonvolatile solute is called ebullioscopy, and the temperature variation is calculated by:
ΔT = W.i
Where W = nsolute/msolvent, and i is the Van't Hoff factor. Because all the substances have the same molarity, n is equal for all of them.
i = final particles/initial particles
C₆H₁₂O₆ don't dissociate, so final particles = initial particles => i = 1;
AlCl₃ dissociates at Al⁺³ and 3Cl⁻, so has 4 final particles and 1 initial particle, i = 4/1 = 4;
NaCl dissociates at Na⁺ and Cl⁻ so has 2 final particles and 1 initial particle, i = 2/1 = 2;
MgCl₂ dissociates at Mg⁺² and 2Cl⁻, so has 3 final particles and 1 initial particle, i = 3/1 = 3.
So, the solution with AlCl₃ will have the highest ΔT, and because of that the highest boiling point.
You can see the periodic table one by one.
Pb(NO3)2 = PbN2O6
So there are
1Pb
2N
6O
and so you find the molecular mass from the periodic table and add all the numbers
Molacular mass of
Pb = 207
N = 14
O = 16
multiply it with the number of atoms
1Pb = 207 × 1 = 207
2N = 14 × 2 = 28
6O = 16 × 6 = 96
Molecular mass total = 207 + 28 + 96 = <u>3</u><u>3</u><u>1</u>
So the molecular mass is 331.
Answer:
See explanation
Explanation:
According to chemistry libretexts(2020); "The rms velocity is directly proportional to the square root of temperature and inversely proportional to the square root of molar mass. Thus quadrupling the temperature of a given gas doubles the rms velocity of the molecules. ... As the temperature of a gas is increased, the velocity of the molecules is also increased."
Hence considering two gases for which the Vrms of the particles of one is high and that of the other is low, we can conclude that the gas having the higher Vrms is at a higher temperature than the gas having a lower Vrms according to the foregoing.
Answer:
D
Explanation:
pressure is inversely proportional to gas volume
