Answer:
The tangential velocity of a rotating object is:
v = r*w
where r is the radius, and w is the angular velocity.
w = 2*pi*f
where f is the frequency.
We know that the record plater does 11 revolutions in 20 seconds, then it does:
11 rev/20s = 0.55 rev/s = f
then we have:
w = 2*pi*0.55 s^-1 = 2*3.14*0.55 s^-1 = 3.454 s^-1
The radius of a record player is really variable, it is around 10 inches, so i will use r = 10in, which is the rotating part of the record player.
then the tangential velocity is:
v = 10in*3.454 s^-1 = 34.54 in/s
Answer:
The graph with a more steeper slope
Explanation:
If the x axis represented time and the y axis represented speed the steeper the slope the more faster something was moving in a shorter amount of time. On the other hand a less steeper slope means an object is gradually picking up speed in a longer amount of time thus makeing it slower
HOPE THIS HELPED:)
Answer:
The age of living tree is 11104 years.
Explanation:
Given that,
Mass of pure carbon = 100 g
Activity of this carbon is = 6.5 decays per second = 6.5 x60 decays/min =390 decays/m
We need to calculate the decay rate
....(I)
Where, N = number of radio active atoms
=half life
We need to calculate the number of radio active atoms
For ![N_{12_{c}}](https://tex.z-dn.net/?f=N_%7B12_%7Bc%7D%7D)
![N_{12_{c}}=\dfrac{N_{A}}{M}](https://tex.z-dn.net/?f=N_%7B12_%7Bc%7D%7D%3D%5Cdfrac%7BN_%7BA%7D%7D%7BM%7D)
Where,
=Avogadro number
![N_{12_{c}}=\dfrac{6.02\times10^{23}}{12}](https://tex.z-dn.net/?f=N_%7B12_%7Bc%7D%7D%3D%5Cdfrac%7B6.02%5Ctimes10%5E%7B23%7D%7D%7B12%7D)
![N_{12_{c}}=5.02\times10^{22}\ nuclie/g](https://tex.z-dn.net/?f=N_%7B12_%7Bc%7D%7D%3D5.02%5Ctimes10%5E%7B22%7D%5C%20nuclie%2Fg)
For ![N_{c_{14}}](https://tex.z-dn.net/?f=N_%7Bc_%7B14%7D%7D)
![N_{c_{14}}=1.30\times10^{-12}N_{12_{c}}](https://tex.z-dn.net/?f=N_%7Bc_%7B14%7D%7D%3D1.30%5Ctimes10%5E%7B-12%7DN_%7B12_%7Bc%7D%7D)
![N_{c_{14}}=1.30\times10^{-12}\times5.02\times10^{22}](https://tex.z-dn.net/?f=N_%7Bc_%7B14%7D%7D%3D1.30%5Ctimes10%5E%7B-12%7D%5Ctimes5.02%5Ctimes10%5E%7B22%7D)
![N_{c_{14}}=6.526\times10^{10}\ nuclei/g](https://tex.z-dn.net/?f=N_%7Bc_%7B14%7D%7D%3D6.526%5Ctimes10%5E%7B10%7D%5C%20nuclei%2Fg)
Put the value in the equation (I)
![R=\dfrac{0.693\times6.526\times10^{10}\times60}{5700\times3.16\times10^{7}}](https://tex.z-dn.net/?f=R%3D%5Cdfrac%7B0.693%5Ctimes6.526%5Ctimes10%5E%7B10%7D%5Ctimes60%7D%7B5700%5Ctimes3.16%5Ctimes10%5E%7B7%7D%7D)
![R=15.0650\ decay/min g](https://tex.z-dn.net/?f=R%3D15.0650%5C%20decay%2Fmin%20g)
100 g carbon will decay with rate
![R=100\times15.0650=1507\ decay/min](https://tex.z-dn.net/?f=R%3D100%5Ctimes15.0650%3D1507%5C%20decay%2Fmin)
We need to calculate the total half lives
![(\dfrac{1}{2})^{n}=\dfrac{390}{1507}](https://tex.z-dn.net/?f=%28%5Cdfrac%7B1%7D%7B2%7D%29%5E%7Bn%7D%3D%5Cdfrac%7B390%7D%7B1507%7D)
![2^n=\dfrac{1507}{390}](https://tex.z-dn.net/?f=2%5En%3D%5Cdfrac%7B1507%7D%7B390%7D)
![2^n=3.86](https://tex.z-dn.net/?f=2%5En%3D3.86)
![n ln 2=ln 3.86](https://tex.z-dn.net/?f=n%20ln%202%3Dln%203.86)
![n=\dfrac{ln 3.86}{ln 2}](https://tex.z-dn.net/?f=n%3D%5Cdfrac%7Bln%203.86%7D%7Bln%202%7D)
![n =1.948](https://tex.z-dn.net/?f=n%20%3D1.948)
We need to calculate the age of living tree
Using formula of age
![t=n\times t_{\frac{1}{2}}](https://tex.z-dn.net/?f=t%3Dn%5Ctimes%20t_%7B%5Cfrac%7B1%7D%7B2%7D%7D)
![t=1.948\times5700](https://tex.z-dn.net/?f=t%3D1.948%5Ctimes5700)
![t=11103.6 =11104\ years](https://tex.z-dn.net/?f=t%3D11103.6%20%3D11104%5C%20years)
Hence, The age of living tree is 11104 years.
A shovel would classify as choice (A) because the head of the shovel is the wedge while the body of the shovel is the lever
Hey there!
The answer would be D. 10 countries with the largest populations are the countries that produce the most greenhouse gases.
This is the only statements that supports the idea of large populations affecting the emissions of greenhouse gases.
Hope this helps!