coulomb's law
f repulsive = q1q2/4 pi epsilon nought r squared
0.1= q1q2/4 pi epsilon nought 0.911 squared
q1+q2= 7.50 µC
0.1= q1(7.5µC-q1)/4 pi epsilon nought 0.911 squared
solve for q1
We are given volume of gasoline = 15.58 L and
Density = 0.74 g/mL.
Density is given in grams(g) per milliliter (mL). So, we need to convert given volume in mL also.
We know, 1 litre = 1000 milliliters
Therefore, 15.58 L = 15.58 * 1000 mL = 15580 mL
We could rewrite,
Volume of gasoline = 15580 mL.
Formula for density is..
Density (ρ)= 
Plugging values in formula,
0.74 g/mL = 
Muliplying both sides by 15580.

11529.2g = mass.
Therefore, 11529.2g grams does 15.58 L of gasoline weigh.
<span>The ball's gravitational potential energy at its peak height was 0.4 joules, and its .... Ignore air resistance and determine (a) the kinetic energy at 28.1 m, (b) the .... At position B, just before it lands, it is falling at 15m/s. a) if the blocks potential ...</span>
Answer:
columns are converted into rows , and rows are converted into columns
Answer:
The refracted angle will be less than the angle of incidence and the speed of light is slower in the new medium (which is water) and is closer to the normal.
Try remembering this by using FST SFA (Fast Sofa)
Fast -> Slow = Towards the normal
Slow -> Fast = Away from normal