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Gemiola [76]
3 years ago
13

Two point charges +3 micro coulomb and +8 micro coulomb repel each other with a force of 40N . If a charge of -5 micro coulomb i

s added to each of them, then the force between them will become?
Physics
1 answer:
fgiga [73]3 years ago
5 0

Answer:

1 N

Explanation:

Given that two point charges +3 micro coulomb and +8 micro coulomb repel each other with a force of 40N.

Let us first calculate the distance between the two point charges

F = (KQq)/r^2

Where K = 9.0 × 10^9Nm^2C^-2

40 = (9×10^9 × 3×10^-6 × 8×10^-6)/r^2

Make r^2 the subject of formula

r^2 = 0.216/40

r = sqrt (5.4^-3)

r = 0.0735 metres

If a charge of -5 micro coulomb is added to each of them, then the force between them will become?

Using the same formula again

F = ( KQq)/r^2

Where Q = 8 - 5 = +3 × 10^-6 C

q = 3 - 5 = - 2 × 10^-6 C

F = ( 9×10^9 × 3×10^-6 × 2×10^-6 )/5.4×10^-2

F = 0.054/0.054

F = 1 N

The force of attraction between the two point charges will be 1 N

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3 years ago
Three fire hoses are connected to a fire hydrant. Each hose has a radius of 0.017 m. Water enters the hydrant through an undergr
alexira [117]

Answer:

2.36 x 10^5 kg

Explanation:

radius of hose, r = 0.017 m

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number of hoses, n = 3

velocity of water in underground pipe, V = 2.7 m/s

Let v is the velocity of water in each hose.

According to the equation of continuity

A x V = n x a x v

π R² x V = n x π x r² x v

0.088 x 0.088 x 2.7 = 3 x 0.017 x 0.017 x v

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(a) Amount of water poured onto a fire in one hour by all the three hoses              

                    = n x a x v x density of water x time

                    = 3 x 3.14 x 0.017 x 0.017 x 24.12 x 1000 x 3600

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hope this helps!

7 0
3 years ago
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