All categories

3 years ago

When can a trapezoid also be called a parallelogram?

Mathematics

2 answers:

Vlada [557]3 years ago

7 0

Answer:

Explained

Step-by-step explanation:

In trapezoid only one pair of side is parallel to each other whereas in A parallelogram both pair of sides are parallel to each other. Although both are quadrilaterals with four sides. But according to above stated condition A a trapezoid can not be called a parallelogram.

hope you got the point and ask your doubts in comments

saveliy_v [14]3 years ago

4 0

Answer:

Yes, because it has one pair of parallel sides.

Step-by-step explanation:

You might be interested in

Need help on 9 don’t know if I did it right or not but I need help :p

solmaris [256]

Answer:

9b) -8 = y

9a) 72° = m∠ABC

Step-by-step explanation:

Since you have an angle trisector, in this case, m∠CBE ≅ m∠DBA, therefore you set x equal to 8, plus, according to Morley's Trisector Theorem, all three angles form an equilateral triangle, so m∠BOC also has to equal 24°:

${8}^{2} - 5(8) = 64 - 40 = 24 \\ \\ 6(8) - 24 = 48 - 24 = 24 \\ \\ 2(8) - y = 24 >> 16 - y = 24 >> -8 = y$

Then, m∠ABC comes from multiplying 3 by 24 [three twenty-four's], which results in 72°.

I am joyous to assist you anytime.

4 0

3 years ago

Matthew invests $500 into an account with a 2.5% interest that is compounded quarterly. How much money will he have in this acco

Karo-lina-s [1.5K]

Answer:

$641.4

Step-by-step explanation:

500(1 + 0.025/4)⁴⁰

= 641.5134103

3 0

3 years ago

Read 2 more answers

(1 point) A particle starts at the point P=(−2,−1,3)P=(−2,−1,3) when t=0t=0 and moves along a straight line toward Q=(−4,0,6)Q=(

Ahat [919]

Answer:

The position is given by r(t) = (-2 -t √14, 1 + √3.5, 3 + 3√3.5)

Step-by-step explanation:

The direction is given by the difference between the starting point and the end point, thus it is (-4,0,6)-(-2,-1,3) = (-2,1,3). The norm of this vector is √( (-2)²+1²+3²) = √14 = 3.7416 secons

Since the speed is 7 cm/sec, we need to multiply this vector by 7/√14 = √3.5 in order to obtain how much does the particle advance each second.

As a consecuence, it advances (-2,1,3) * √3.5 = (- √14, √3.5, 3 √3.5)

And, as a result, the position after t seconds is given by the function

r(t) = (-2,1,3) + t (-√14, √3.5, 3 √3.5) = (-2 -t √14, 1 + √3.5, 3 + 3√3.5)

8 0

3 years ago

EOC Review

lana [24]

Answer:

0ft and 60ft

Step-by-step explanation:

Given

The attached function

Required

Determine the valid values of the domain of the function

To do this, we simply consider the starting point and the end point of the trajectory on the x-axis (i.e. the horizontal distance).

From the attached graph, the horizontal distance starts from 0 and ends at 180.

This implies that the domain is: $0 \le x \le 180$

From the options, the values that fall in this bracket are 0ft and 60ft

3 0

2 years ago

Which is The graph of f(x) = 5(2)^x

Snezhnost [94]

The graph reflecting the mathematical equation f(x) = 5*2^x is attached on this answer. Graph shows the exponential manner with the y-intercept is at y = 5. we can plot this graph by substituting points of x from a certain range (positive and negative) and get their corresponding y's

5 0

3 years ago

Read 2 more answers