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bogdanovich [222]
3 years ago
7

An expensive vacuum system can achieve a pressure as low as 1.00 × 10 − 8 N / m 2 at 19.5 °C . How many atoms are there in a cub

ic centimeter at this pressure and temperature?
Physics
1 answer:
Stels [109]3 years ago
8 0

Answer:

2475042

Explanation:

P = Pressure = [/tex]1\times 10^{-8}\ N/m^2[/tex]

V = Volume = 1 cm³

T = Temperature = 19.5 °C

R = Gas constant = 8.341 J/mol K

N_A = Avogadro's number = 6.022\times 10^{23}

n = Amount of substance

From ideal gas law we have

PV=nRT\\\Rightarrow n=\frac{PV}{RT}\\\Rightarrow n=\frac{1\times 10^{-8}\times 1\times 10^{-6}}{8.314(273.15+19.5)}\\\Rightarrow n=4.11\times 10^{-18}

Number of atoms is given by

n\times N_A\\ =4.11\times 10^{-18}\times 6.022\times 10^{23}\\ =2475042\ atoms

The number of atoms in this vacuum is 2475042

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