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masha68 [24]
3 years ago
12

HELLPPPPPLSSSS SOMSE

Mathematics
1 answer:
Nina [5.8K]3 years ago
7 0

Answer:

Option F

Step-by-step explanation:

F). x + y = 3 -------(1)

    x - 3y = -2 --------(2)

    Equation (1) minus equation (2)

    (x + y) - (x - 3y) = 3 - (-2)

    4y = 5

    y = 1.25

    Hence, y is positive.

G). x + y = 3 --------(1)

    x + y = -2 --------(2)

    Both the equations represent parallel lines.

    There are no solutions of the given equations.

H). x - 3y = -2 -------(1)

     x + y = -2 -------(2)

    Equation (2) minus equation (1)

    (x + y) - (x - 3y) = -2 - (-2)

     4y = 0

     y = 0

    Since, 0 is neither positive nor negative, y will be neither positive nor negative.

J). x + y = 3 -------(1)

    x - y = 3 --------(2)

    Equation (1) - Equation (2)

    (x + y) - (x - y) = 3 - 3

    2y = 0

    Hence, y is neither negative nor positive.  

    Therefore, Option F is the answer.

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Answer:

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Step-by-step explanation:

Given:

- The ODE of the life of Carbon-14:

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- Assuming Q(t) satisfies:

                                       Q' = -r*Q

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- Make the relation for Q:

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- Using initial conditions given:

                                       Q(0) = Q_o

                                       Q_o = C*e^(-r*0)

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- The relation is:

                                       Q(t) = Q_o*e^(-r*t)

- We are also given that the half life of carbon is t = 5730 years:

                                       Q_o / 2 = Q_o*e^(-5730*r)

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- Hence, our expression for Q(t) would be:

                                       Q(t) = Q_o*e^(-0.000120968*t)                                    

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