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prohojiy [21]
3 years ago
13

Identify the spectator ions in the following molecular equation.

Chemistry
1 answer:
SOVA2 [1]3 years ago
3 0
We can rewrite the equation KBr(aq) + AgNO3(aq) → AgBr(s) + KNO3(aq) into its net ionic equation into
 K+ + Br- + Ag + + NO3-  = AgBr + K + NO3-only aqueous solutions can dissociate. Spectator ions are present in both sides, hence these are K+ and NO3-. THe rules of assigning oxidation numbers is to identify the number of valence electrons of elements and may be arbitrary depending on the charge of the molecule. 
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A) Faça o balanceamento da reação da hidroquinona com peróxido de hidrogênio. ( C6H4(OH)2(aq) + H2O2(aq) --&gt; C6H4O2(aq) + H2O
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The reaction is  (a reação é)

(C6H4(OH)2(aq) + H2O2(aq) --> C6H4O2(aq) + H2O(L) ........(i)

The other reaction given are (A outra reação dada é)

C6H4(OH)2(aq)   ---> C6H4(OH)2(aq) + H2(g)   .......(ii)   ΔH = 177 kJ

2H2O2(aq) ----> 2H2O(l) + O2(g) ..................................(iii)  ΔH = -189.3

2H2(g)  + O2(g) ----> 2H2O (l)   .....................................(iv)  ΔH =-572 kJ

We can obtain equation (i) from equation (ii), (iii) and (iv) as

[Podemos obter a equação (i) da equação (ii), (iii) e (iv) como]

equation (i) = equation (ii) + 0.5 X equation (iii) + 0.5 X equation (iv)

[equação (i) = equação (ii) + 0.5 X equação (iii) + 0.5 X equação (iv)]

So ΔH1 = ΔH(ii) + 0.5 X ΔH(iii) + 0.5 X ΔH(iv)

             = 177 + 0.5 X (-189.3) + 0.5 X(-572) = -203.65 kJ


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