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3 years ago

Identify the spectator ions in the following molecular equation.

1 answer:

3 0

We can rewrite the equation KBr(aq) + AgNO3(aq) → AgBr(s) + KNO3(aq) into its net ionic equation into
K+ + Br- + Ag + + NO3- = AgBr + K + NO3-only aqueous solutions can dissociate. Spectator ions are present in both sides, hence these are K+ and NO3-. THe rules of assigning oxidation numbers is to identify the number of valence electrons of elements and may be arbitrary depending on the charge of the molecule.

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What is the main difference between scholarly research and scientific research? Scientists wear white coats. One is performed wh

erastovalidia [21]

The last statement is correct...

please vote my answer brainliest. thanks!

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3 years ago

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given a density of 350 grams/cm3 and a mass of 25 grams. What is the volume using the equation involving density?

Eduardwww [97]

0.07cm³

Explanation:

Given parameters:

Density of the body = 350g/cm³

Mass of the body = 25g

Unknown:

Volume of the body = ?

Solution:

Density is the amount of substance contained in a volume of body. It is expressed as:

Density = $\frac{mass}{volume}$

Since the unknown is volume, we make it the subject of the expression;

Volume = $\frac{mass}{density}$

Volume = $\frac{25}{350}$ = 0.07cm³

learn more:

Density brainly.com/question/2690299

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3 years ago

Why is sugar soluble in water while oil cannot form a solution?

Viefleur [7K]

Answer:

the water and alcohol interact, which means the water doesn't even dissolve the sugar or color as well as it normally would. Oil molecules are not polar so they cannot dissolve either the coloring or the sugar.

Explanation:

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3 years ago

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The whiye pigment TiO2 is prepared by the reaction of titanium tetrachloride, TiCl4, with water vapor in the gas phase:

omeli [17]

Answer:

$\boxed{\text{62.1 kJ}}$

Explanation:

The formula for calculating the enthalpy change of a reaction by using the enthalpies of formation of reactants and products is

$\Delta_{\text{r}}H^{\circ} = \sum \Delta_{\text{f}} H^{\circ} (\text{products}) - \sum\Delta_{\text{f}}H^{\circ} (\text{reactants})$

TiCl₄(g) + 2H₂O(g) ⟶ TiO₂(s) + 4HCl(g)

ΔH°f/kJ·mol⁻¹: -763.2 -241.828 -939.7 -92.307

$\begin{array}{rcl}\Delta_{\text{r}}H^{\circ} & = & [-939.7 + 4(-92.307)] - [-763.2 + 2(-241.828)\\& = & [-939.7 - 369.228] - [-763.2 - 483.656]\\& = & -1308.928 + 1246.856\\& = & \mathbf{-62.1}\\\end{array}\\\text{The amount of heat evolved is } \boxed{\textbf{62.1 kJ}}$

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3 years ago

How would you separate copper sulfate crystals from its solution?

tia_tia [17]

Answer: You would separate it by dissolving them.

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3 years ago