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Match the chemical Equation with his correct type

Alex

Answer:

The answer to your question is given below

Explanation:

1. C. 2NaCl + I2 —> 2NaI + Cl2 => C. Single displacement.

From the above equation, we can see that I2 replaces Cl in NaCl to produce NaI. This is simply called a single displacement reaction.

2. E. 2C4H10 + 13O2 —> 8CO2 + 10H2O => E. Combustion.

The above equation shows the burning of Hydrocarbon in the presence of O2. This is simply called Combustion as CO2 and H2O is produced.

3. D 2H2O —> 2H2 + O2 => D. Decomposition.

From the above equation, we can see that a single compound H2O produces two elements H2 and O2. This is simply called a decomposition reaction.

4. A. ZnS + 2HCl —> ZnCl2 + H2S => A. Double Decomposition.

From the above equation, we can see that Cl replaces S in ZnS to produce ZnCl2 and S replaces Cl in HCl to produce H2S. This is simply called double displacement reaction.

5. B. H2 + Br2 —> 2HBr => B. Synthesis.

From the above equation, we can see that two element H2 and Br2 combine to produce a single compound HBr. This is simply called a synthesis reaction.

7 0

3 years ago

Select three parts of a simple electrolytic cell and explain their functions in the space below.

kotegsom [21]

A cathode is the location in an electrolytic cell where reduction reactions take place.

An anode is the location in an electrolytic cell where oxidation reactions occur.

An electrolyte solution is any substance containing free ions that make the substance electrically conductive.

An external electrical energy source like a battery or a transformer is used to drive the non-spontaneous reaction.

8 0

3 years ago

(a) Write the dissolution reaction for solid Na2CO3 below. (Use the lowest possible coefficients. Include states-of-matter under

Andreas93 [3]

Answer:

For a: The chemical equation for the dissolution of sodium carbonate is $Na_2CO_3(s)\rightarrow Na_2CO_3(aq.)$

For b: The net acid-base reaction is $CO_3^{2-}(aq.)+H_2O(l)\rightarrow OH^-(aq.)+HCO_3^-(aq.)$

Explanation:

For a:

Dissolution reaction is defined as the reaction in which a solid compound gets dissolved in water to form aqueous solution.

The chemical equation for the dissolution of sodium carbonate follows:

$Na_2CO_3(s)\rightarrow Na_2CO_3(aq.)$

Ionization reaction is defined as the reaction in which an ionic compound dissociates into its ions when dissolved in aqueous solution.

The chemical equation for the ionization of sodium carbonate follows:

$Na_2CO_3(aq.)\rightarrow 2Na^+(aq.)+CO_3^{3-}(aq.)$

For b:

Now, the anion formed which is $CO_3^{2-}$ reacts with water to form conjugate acid.

The chemical equation for the reaction of anion with water follows:

$CO_3^{2-}(aq.)+H_2O(l)\rightarrow OH^-(aq.)+HCO_3^-(aq.)$

Hence, the net acid-base reaction of the anion formed and water is written above.

3 0

3 years ago

A bomb calorimeter has a heat capacity of 675 J/°C and contains 925 g of water. If the combustion of 0.500 mole of a hydrocarbon

ikadub [295]

Answer: The enthalpy of the reaction is 269.4 kJ/mol

Explanation:

To calculate the heat absorbed by the calorimeter, we use the equation:

$q_1=c\Delta T$

where,

q = heat absorbed

c = heat capacity of calorimeter = 675 J/°C

$\Delta T$ = change in temperature = $T_2-T_1=(53.88-24.26)^oC=29.62^oC$

Putting values in above equation, we get:

$q_1=675J/^oC\times 29.62^oC=19993.5J$

To calculate the heat absorbed by water, we use the equation:

$q_2=mc\Delta T$

where,

q = heat absorbed

m = mass of water = 925 g

c = heat capacity of water = 4.186 J/g°C

$\Delta T$ = change in temperature = $T_2-T_1=(53.88-24.26)^oC=29.62^oC$

Putting values in above equation, we get:

$q_2=925g\times 4.186J/g^oC\times 29.62^oC=114690.12J$

Total heat absorbed = $q_1+q_2$

Total heat absorbed = $[19993.5+114690.12]J=134683.62J=134.7kJ$

To calculate the enthalpy change of the reaction, we use the equation:

$\Delta H_{rxn}=\frac{q}{n}$

where,

q = amount of heat absorbed = 134.7 kJ

n = number of moles of hydrocarbon = 0.500 moles

$\Delta H_{rxn}$ = enthalpy change of the reaction

Putting values in above equation, we get:

$\Delta H_{rxn}=\frac{134.7kJ}{0.500mol}=269.4kJ/mol$

Hence, the enthalpy of the reaction is 269.4 kJ/mol

6 0

3 years ago

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Which of the following compounds is a glycol?

Genrish500 [490]

Answer:

HOH2C-CH2-CH2-CH2OH

7 0

3 years ago

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