1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
shusha [124]
3 years ago
15

a 10.0kg object moving at 5.00 m/s experiences a force of 20.0N. How far must it be pushed by this force for its speed to reach

15.0 m/s?
Physics
1 answer:
Pie3 years ago
6 0

Answer: 50 m.

Explanation:

Assuming there is only 20N force acting on the object, use F = m * a where F is force, m is mass and a is acceleration.

You'll get a = 2.

Next, write what you know.

acceleration (a) = 2

initial velocity (u) = 5

final velocity (v) = 15

distance (s) = ?

Now, use v² = u² + 2as and find s.

You might be interested in
A flow of electric charge in a wire normally requires a _________.
just olya [345]
Flow of electric charge in a wire requires " ELECTRONS "
6 0
3 years ago
A person on earth would weigh a lot more on the sun due to increased ________________. gravity mass atoms energy
klemol [59]
A person on Earth would weigh a lot more on the sun due to increased gravity.

The sun is a massive object as compared to the sun. It is assumed that the gravity must be a lot greater as well. It is the strong gravitational pull of the sun that keeps our planets from drifting off into space. No matter where you are the mass of an object will remain constant, so will the energy and the number of atoms they hold. 

The answer is gravity.
4 0
3 years ago
Read 2 more answers
The windshield of a speeding car hits a hovering insect. Consider the time interval from just before the car hits the insect to
HACTEHA [7]

Answer:

A. False

B True

C. False

D.False

E. True

F. False

G. False

H. False

I. True

Explanation:

A. False: The system being analyzed consists of the bug and the car.  These are the two bodies involved in the collision.

B. True: The system being analyzed consists of the bug and the car

C. False: The magnitudes of the change in velocity are different from the car and the bug. The velocity of the bug changes from 0 to the velocity of the car, while there is no noticeable change in the velocity of the car

D.False: There is barely any change in the momentum of the car since the mass of the bug is very small.

E. True: Since the mass of the bug is small, and was initially at rest, the magnitude of the change in monentum will be large because the new velocity will be that of the car.

F. False: The system being analyzed consists of the bug and the car. Those are the two bodies involved in the collision

G. False: The car barely changes in velocity since the mass of the bug is small.

H. False: The car barely changes in momentum because the collision does not affect its speed so much. on the other hand the momentum change of the bug is large since its mass is small.

I. True: The bug which was initially at rest will begin moving with the velovity of the speeding car, while the car barely changes in its velocity

5 0
2 years ago
Newton's 3rd law states that every action, there is an equal and _ reaction?
klasskru [66]

Answer:

Opposite

Explanation:

According to Newton's third law of motion, it states that for every action, there is an equal and opposite reaction. This implies that when you exert a force of 400 N on an object, it will react by giving an equal -400 N to counter the oncoming force. Notice that the equal force is negative to mean it's opposite of the action.

8 0
3 years ago
3. A car moves from rest with uniform acceleration along a horizontal road. After travelling a distance of 100 metres, it has ki
mrs_skeptik [129]

Answer: (c) 2000 N

Explanation:

Given Data :

▪ Initial velocity = zero ( body is at rest)

▪ Distance travelled = 100m

▪ Final kinetic energy = 200000J

To Find :

▪ Resultant force acting on the car.

Therefore:

W = F × d = ΔK ----------------- eq 1.

where,

W = work done

F = applied force

d = distance

ΔK = change in kinetic energy

Calculation :

→ F × d = Kf - Ki ----------------- eq 2.

Where:

Kf = Final kinetic energy = 200000

Ki = initial kinetic energy = 0

Substituting our values into the formula from equation (2)

→ F × 100 = 200000 - 0

→ F = 200000/100

→ F = 2000N

8 0
3 years ago
Other questions:
  • A carpenter apprentice was killed when he was struck in the head by a nail that was fired from a powder actuated tool. The tool
    5·1 answer
  • If a bus you are riding is traveling at a constant speed and then stops suddenly, you feel "thrown" forward. Which of the follow
    15·1 answer
  • Jane, looking for tarzan, is running at top speed (5.2 m/s) and grabs a vine hanging 4.5 m vertically from a tall tree in the ju
    6·1 answer
  • A 1000kg ar accelerates from rest to 25.0m/s in 4.20
    10·1 answer
  • What is a convenient way to show how a fixed quantity is broken down into parts?
    10·1 answer
  • A bowling ball is on the end of a rope of length 5 meters, the other end of which is attached to a hook in the ceiling. The ball
    5·1 answer
  • Brizan has just lost his job. He is proactive in trying to resolve this source of stress: He immediately uses the Internet to lo
    12·2 answers
  • A stone is thrown horizontally with an initial speed of 10 m/s from the edge of a cliff. A stopwatch measures the stone's trajec
    11·1 answer
  • HELP ME, I'M BEING TIMED
    12·2 answers
  • if a cyclist is travelling a road due east at 12km/h and a wind is blowing from south-west at 5km/h. find the velocity of the wi
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!