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shusha [124]
3 years ago
15

a 10.0kg object moving at 5.00 m/s experiences a force of 20.0N. How far must it be pushed by this force for its speed to reach

15.0 m/s?
Physics
1 answer:
Pie3 years ago
6 0

Answer: 50 m.

Explanation:

Assuming there is only 20N force acting on the object, use F = m * a where F is force, m is mass and a is acceleration.

You'll get a = 2.

Next, write what you know.

acceleration (a) = 2

initial velocity (u) = 5

final velocity (v) = 15

distance (s) = ?

Now, use v² = u² + 2as and find s.

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Students have 4 different pairs of sunglasses, each with lenses where the polarization filter is oriented in different direction
AysviL [449]

Answer:

the lens you must select has an angle of 143º measured with respect to the horizontal, this angle is 53º with respect to the vertical.

Explanation:

The glare is caused by the reflection of light in the water, the polarization of the reflected light is polarized in a direction parallel to the surface of the water, the polarization is total for the angles

         n = tan  \theta_{p}

         \theta_{p} = tan⁻¹ n

the refractive index for seawater is 1.33

         \theta_{p}= tan⁻¹  1.33

         \theta_{p} = 53º

for this angle the light is totally polarized, for the other angles the polarization is partial.

Based on this, the lenses must eliminate this polarization, so its polarization direction must have 90º with respect to this polarization,

          \theta_{lens} = 53 +90

           \theta_{lens}= 143º

Therefore, the lens you must select has an angle of 143º measured with respect to the horizontal, this angle is 53º with respect to the vertical.

A lens that could work is one that is polarized 45º with respect to the vertical.

6 0
3 years ago
Determine whether the interference is constructive or destructive at each location indicated.
OlgaM077 [116]

Answer:

A. Constructive

B. Destructive

C. Destructive

D. Constructive

Explanation:

Constructive interference takes place at locations along the path of two superposed waves where the waves are in phase such that a high or low point of one of the waves corresponds with a high or low point of the other wave which gives a resulting wave amplitude which is the sum of the amplitudes of the individual waves

Destructive interference takes place at locations along the path of two superposed waves where one wave is out of phase with the other wave such that a high or low point of one of the waves coincides with a low or high point of the other wave respectively thereby cancelling the effect of the other wave and giving a resulting wave that has an amplitude which is the difference in the amplitudes of the individual waves

Therefore;

At point A, the peak of each wave partially coincides resulting in constructive interference

At point B, the peak of the blue wave and the trough of the red wave partially coincides resulting in destructive interference

At point C, the through of the blue wave and the peak of the back wave partially coincides resulting in destructive interference

At point D, the trough of each wave partially coincides resulting in constructive interference.

6 0
2 years ago
What is the final temperature if it requires 5000 J of heat to warm 2.38892 x10-2 kg of water that starts at 5oC? Remember Cp fo
Tanya [424]

Explanation:

Hi ythere sorry do not know

3 0
3 years ago
an apple in a tree has a gravitational potential energy of 175J and a mass of 0.36g . how high from the ground is the apple
Neko [114]
The equation for potential energy is denoted as; 

Pe = mgh,

where m = the mass, g = acceleration due to gravity, and h = vertical height of the apple. We are given the units for everything but height, which is also what we are solving for. We can then algebraically rearrange our initial equation to solve for h;

h = (Pe)/(mg)

Plug in your given units, and solve!





Post-check:

h = Pe/mg

h = 175J/(0.36g)(-9.81m/s^2)

h = appr. 49.5 meters

Note: Potential energy is a vector quantity; the displacement of the apple will be a negative number, but the distance itself, a scalar quantity, will be the absolute value of that.
5 0
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In concave lenses a Distance object appears ​
JulsSmile [24]

Answer:

it appears to be farther away than it actually is, and therefore smaller then the object itself.

4 0
2 years ago
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