1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Bogdan [553]
3 years ago
5

A sled of mass m is being pulled horizontally by a constant horizontal force of magnitude F. The coefficient of kinetic friction

is mu_k. During time interval t, the sled moves a distance s, starting from rest.Find the average velocity vavg of the sled during that time interval.Express your answer in terms of the given quantities and, if necessary, appropriate constants. You may or may not use all of the given quantities.
Physics
1 answer:
steposvetlana [31]3 years ago
6 0

Answer:

The average velocity of the sled is vavg = s/t.

Explanation:

Hi there!

The average velocity is calculated as the traveled distance over time:

vavg = Δx/Δt

Where:

vavg = average velocity.

Δx = traveled distance.

Δt = elapsed time.

We already know the traveled distance (s) and also know the time it takes the sled to travel that distance (t). Then, the average velocity can be calculated as follows:

vavg = s/t

Have a nice day!

You might be interested in
A volcano erupts spewing ash into the air and sending lava flowing down the side of the mountain. Looking at the image explain h
Anit [1.1K]

Answer:

A lateral eruptions or lateral blast is a volcanic eruption which is directed laterally from a volcano rather than upwards from the summit. Lateral eruptions are caused by the outward expansion of flanks due to rising magma. Breaking occurs at the flanks of volcanoes making it easier for magma to flow outward.

Explanation:

7 0
3 years ago
What is the equivalent resistance between points A and C if R1=1430, R2=1350, R3=1100, R4=1350, and R5=1150.
Marianna [84]

R1 + R4 = 1430 + 1350 = 2780 = R14    series combination of R1 & R4

R2 + R5 = 1350 + 1150 = 2500 = R25

The circuit has been reduced to 3 resistors in parallel

R314 = 2780 * 1100 / (2780 + 1100) = 788  this is the resistance of the parallel combination of R14 and R3

R31425 = 2500 * 788 / (2500 + 788) = 599 which is the equivalent of the circuit  - you can also use the formula for 3 resistors in parallel but this seems simpler

7 0
3 years ago
A 25 kg mass is accelerated by a force at a rate of 5 m/s2. What is the magnitude of the force that accelerates the man?
svlad2 [7]
Force=mass*acceleration
F=ma
F=25*5
F=100 N
8 0
3 years ago
HELP PLEASE
denis-greek [22]
B) Distance: the farther, the weaker!
4 0
3 years ago
Read 2 more answers
6. Which of these is the region of a sound wave in which the density and pressure are
Ilia_Sergeevich [38]

Answer:  Compression

Explanation:

6 0
3 years ago
Other questions:
  • A ball thrown vertically upward is caught by the thrower after 1.76 s. find the initial velocity of the ball. the acceleration o
    9·1 answer
  • You pull with a force of 255 N on a piece of luggage of mass 68 kg, but it does not move. If the coefficient of friction between
    15·2 answers
  • Thinking about the impacts of socioeconomic status, you should A. consider the outside factors that are impacting that child's a
    13·2 answers
  • What is the effeciency of the machine that has an input of 120 and an output of 96?
    12·1 answer
  • I’ll give brainliest
    6·1 answer
  • When an object is turning around, is it also at rest at the point?
    5·2 answers
  • If the position of a particle on the x-axis at time t is −5t2, then the average velocity of the particle for 0 ≤ t ≤ 3 is
    11·1 answer
  • A 500 kg car is moving at 30 m/s. The driver sees a barrier ahead. If the car takes 100 m to come to rest, what is the magnitude
    10·1 answer
  • A 10248 kg car is pulled by a low tow truck that has an acceleration of 2.0m/s what is the net force on the car
    15·1 answer
  • If a body has a velocity 50 m s-1
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!