Answer:
Efficiency = 10.2 %
Explanation:
Given the following data;
Mass = 70 kg
Height = 50 m
Velocity = 10 m/s
We know that acceleration due to gravity is equal to 9.8 m/s².
To find the efficiency of energy conversion from potential to kinetic;
First of all, we would determine the potential energy;
P.E = mgh
P.E = 70 * 9.8 * 50
P.E = 34300 J
For the kinetic energy;
K.E = ½mv²
K.E = ½ * 70 * 10²
K.E = 35 * 100
K.E = 3500
Therefore, Input energy, I = 34300 J
Output energy, O = 3500 J
Next, we find the efficiency;
Efficiency = O/I * 100
Substituting into the formula, we have;
Efficiency = 3500/34300 * 100
Efficiency = 0.1020 * 100
Efficiency = 10.2 %
Speed: measure of how fast an object travels
Velocity: measure of how fast, and in what direction, an object travels
Distance: how far an object has traveled on some path
Position: where an object is located in some reference system
Displacement: the difference between an objects starting position and it’s ending position
Answer:
A. both fields use the same technology
Explanation:
The amount of energy that a wave may transfer to a unit area of a surface each second is measured as the wave's intensity. Watts per square meter is a unit used to express intensity. A sound wave's frequency is equal to its rate of vibration, and its intensity is determined by its amplitude.
<h3>What is the intensity of sound waves affect the frequency?</h3>
The energy of a vibration is quantified in decibels as intensity or loudness (dB). A sound has a high intensity if it is loud.
Therefore, perceive noise as louder the higher the frequency, although frequency does not indicate how loud a sound is.
Learn more about sound waves here:
brainly.com/question/1585667
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