Answer:
The 10 rules of badminton are as follows:
1. A game starts with a coin toss. Whoever wins the toss gets to decide whether they would serve or receive first OR what side of the court they want to be on. The side losing the toss shall then exercise the remaining choice.
2. At no time during the game should the player touch the net, with his racquet or his body.
3. The shuttlecock should not be carried on or come to rest on the racquet.
4. A player should not reach over the net to hit the shuttlecock.
5. A serve must carry cross court (diagonally) to be valid.
6. During the serve, a player should not touch any of the lines of the court, until the server strikes the shuttlecock. During the serve the shuttlecock should always be hit from below the waist.
7. A point is added to a player's score as and when he wins a rally.
8. A player wins a rally when he strikes the shuttlecock and it touches the floor of the opponent's side of the court or when the opponent commits a fault. The most common type of fault is when a player fails to hit the shuttlecock over the net or it lands outside the boundary of the court.
9. Each side can strike the shuttlecock only once before it passes over the net. Once hit, a player can't strike the shuttlecock in a new movement or shot.
10. The shuttlecock hitting the ceiling, is counted as a fault.
Explanation:
<h2>
Hello!</h2>
The answer is:
The first option, the walker traveled 360m more than the actual distance between the start and the end points.
Why?
Since each block is 180 m long, we need to calculate the vertical and the horizontal distance, in order to calculate how farther did the travel walk between the start and the end points (displacement).
So, calculating we have:
Traveler:


Actual distance between the start and the end point (displacement):

Now, to calculate how much farter did the traveler walk, we need to use the following equation:

Therefore, we have that distance differnce between the distance covered by the walker and the actual distance is 360m.
Hence, we have that the walker traveled 360m more than the actual distance between the start point and the end point.
Have a nice day!
= Heat released to cold reservoir
= Heat released to hot reservoir
= maximum amount of work
= temperature of cold reservoir
= temperature of hot reservoir
we know that

eq-1
maximum work is given as
=
- 
using eq-1
=
- 
Answer:
The value is 
Explanation:
From the question we are told that
The molar mass of hydrazine is 
The initial temperature is 
The final temperature is 
The specific heat capacity is ![c_h = 0.099 [kJ/(mol K)] = 0.099 *10^3 J/(mol/K)](https://tex.z-dn.net/?f=c_h%20%20%3D%20%200.099%20%5BkJ%2F%28mol%20K%29%5D%20%3D%200.099%20%2A10%5E3%20J%2F%28mol%2FK%29)
The power available is 
The mass of the fuel is 
Generally the number of moles of hydrazine present is

=> 
=> 
Generally the quantity of heat energy needed is mathematically represented as
=>
=>
Generally the time taken is mathematically represented as

=> 
=> t = 2480505.6377 s
Converting to hours

=> 