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sp2606 [1]
3 years ago
9

Jason applies a force of 4.00 newtons to a sled at an angle 62.0 degrees from the ground. What is the component of force effecti

ve in pulling the sled horizontally along the ground?
Physics
1 answer:
Brilliant_brown [7]3 years ago
7 0
If we consider that the surface wherein this box is located is frictionless in such a way that the friction does not affect its motion, we can calculate for the horizontal force by multiplying the force with the sine of the angle.
                     x-component of force = (4 N) x (sin 62°)
                                         = 3.53 N
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Write an expression for the magnitude of charge moved, Q, in terms of N and the fundamental charge e
NeTakaya

We have that for the Question "Write an expression for the <em>magnitude </em>of charge moved, Q, in terms of N and the fundamental charge e" it can be said its equation is

Q=\frac{E}{Nr^2}

       

From the question we are told

Write an expression for the <em>magnitude </em>of charge moved, Q, in terms of N and the fundamental charge e

<h3>An Expression for the <em>magnitude </em>of charge moved</h3>

Generally the equation for the  <em>magnitude </em>of charge moved, Q   is mathematically given as

Q=\frac{E}{Nr^2}

Therefore

An expression for the <em>magnitude </em>of charge moved, Q, in terms of N and the fundamental charge e" it can be

 Q=\frac{E}{Nr^2}

 

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2 years ago
A voltage amplifier needs a high input resistance and a low output resistance. Select one: True False
cupoosta [38]

Answer:

Explanation:

In electric circuit , the potential difference is always developed across the resistance .

Now is we are to amplify the voltage , that means low input voltage is converted into high voltage output .

Therefore we require low resistance at input for low voltage and high out put resistance for high output

Thus the statement given is wrong .

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A rock is suspended from a string, and it accelerates downward. Which one of the following statements is correct? Group of answe
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Explanation:

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T = mgcos\theta + \frac{mv^2}{L}

So at the lowest point of the path we can say

T = mg + \frac{mv^2}{L}

so correct answer is

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