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nevsk [136]
3 years ago
9

A child and her mother are at the park. The child walks around the rectangular park while her mom waits on a bench. The child re

turns to the bench, finishing her walk at the same place she started. The park is 411 meters wide and 475 meters long. What was the displacement of the child?
64 m
886 m
1,772 m
0 m
Chemistry
2 answers:
RSB [31]3 years ago
7 0
C 1,772 is the answer for the question

Luda [366]3 years ago
5 0

The displacement of the child is Om.

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Thallium consists of 29.5%Th-203 and 70.5%Th-205. What is the relative atomic mass of thallium?
grin007 [14]
0.295 * 203 = 53.885
0.705 * 205 = 144.525
53.885 + 144.525 = 204.41
The relative atomic mass of Thallium is 204.41 
7 0
3 years ago
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What is the charge on an atom with an equal number of protons and electrons?
dexar [7]

Answer: the answer is a netrual bond

Explanation: a netural bond happens when the number of electrons are the same as the number of protons.

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The Lucas test has _______ results based on the type of alcohol present because the reaction involves a _________, which is ____
Olin [163]

Answer:

1) positive

2) carbocation

3) most stable

4) faster

Explanation:

A common test for the presence of alcohols can be achieved using the Lucas reagent. Lucas reagent is a mixture of concentrated hydrochloric acid and zinc chloride.

The reaction of Lucas reagent reacts with alcohols leading to the formation of an alkyl chloride. Since the reaction proceeds via a carbocation mechanism, tertiary alcohols give an immediate reaction. Once a tertiary alcohol is mixed with Lucas reagent, the solution turns cloudy almost immediately indicating an instant positive reaction.

Secondary alcohols may turn cloudy within five minutes of mixing the solutions. Primary alcohols do not significantly react with Lucas reagent obviously because they do not form stable carbocations.

Therefore we can use the Lucas reagent to distinguish between primary, secondary and tertiary alcohols.

5 0
3 years ago
What is the boiling point of water at an elevation of 1.55×104 ft ?
horsena [70]
The computation for this problem is:
(1.55x10^4 / 1.0x10^3) x 19.8 mm Hg
= 15.5 x 19.88 mm Hg
= 308.14 mm Hg decrease 
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deduct this amount to 100
100 – 15.407 = 84.593 C 
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4 0
3 years ago
4. A student started with a 0.032 g sample of copper which he took through the series of reactions described in this experiment.
Elodia [21]

Answer:

Y=48.6\%

Explanation:

Hello,

In this case, we can consider the following chemical reaction for the oxidation of copper which only occurs at high temperatures:

2Cu+O_2\rightarrow 2CuO

In such a way, for 0.032 grams of copper, the following grams of copper (II) oxide (black product) are yielded:

m_{CuO}=0.032gCu*\frac{1molCu}{63.546gCu} *\frac{2molCuO}{2molCu}*\frac{79.546gCuO}{1molCuO}  =0.078gCuO

Therefore, the percent yield is:

Y=\frac{0.038g}{0.078g}*100\%\\ \\Y=48.6\%

Best regards.

6 0
3 years ago
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