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KiRa [710]
3 years ago
6

Calculate the hfg and sfg of steam at 120oC from the Clapeyron equation, and compare them to the tabulated values.

Chemistry
1 answer:
den301095 [7]3 years ago
5 0

Answer:

The tabulated values at 120 C of <u><em>hfg = 2202.1</em></u><u> kJ/Kg </u>and <u><em>sfg </em></u><u>= 5.6 </u>

<u>kJ/Kg.K</u>

Explanation:

According to Clapeyron Equation :

h_{fg}=TV_{fg}\left (\frac{\partial P}{\partial T}  \right )_{sat}

=T(V_{g}-V_{f})_{120^{0}}\left ( \frac{\Delta P}{\125^{0}-115^{0}} \right )

Taking P2 at temperature 125 and P1 at 115 degree Celsius .

T = 120 + 273.15 = 393.15 K

P2 = 232.23 kPa and P1 = 169.18kPa

(these are experimental values given in the Data)

= 393.15(0.88133 -0.001060\ m^{3}/Kg)\frac{232.23-169.18 kPa}{10}

h_{fg} = 2206.8 kJ/Kg

S_{fg}=\frac{h_{fg}}{T}

\frac{2206.8}{393.15}

= 5.6131 kJ/Kg.K

The tabulated values at 120 C of <em>hfg = 2202.1</em> kJ/Kg and <em>sfg </em>= 5.6131

kJ/Kg.K

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