Answer: 100 grams of glucose represents 0.55 moles .
Explanation:
The molar extinction coefficient is 15,200
.
The formula to be used to calculate molar extinction coefficient is -
A = ξcl, where A represents absorption, ξ refers molar extinction coefficient, c refers to concentration and l represents length.
The given values are in required units, hence, there is no need to convert them. Directly keeping the values in formula to find the value of molar extinction coefficient.
Rewriting the formula as per molar extinction coefficient -
ξ = 
ξ = 
Performing multiplication in denominator to find the value of molar extinction coefficient
ξ =
Performing division to find the value of molar extinction coefficient
ξ = 15,200 
Hence, the molar extinction coefficient is 15,200
.
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Answer: The standard entropy of vaporization of ethanol is 0.275 J/K
Explanation:

Using Gibbs Helmholtz equation:

For a phase change, the reaction remains in equilibrium, thus 

Given: Temperature = 285.0 K

Putting the values in the equation:


Thus the standard entropy of vaporization of ethanol is 0.275 J/K
562 grams because mass can not be created or destroyed