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2 years ago

What elements is mercuric oxide composed of?

2 answers:

6 0

Binary compounds are compounds composed of just two elements. The simplest kind of decomposition reaction is when a binary compound decomposes into its elements. Mercury(II) oxide, a red solid, decomposes when heated to produce mercury and oxygen gas.

Tomtit [17]2 years ago

5 0

Answer:

Lavoisier reacted mercury with oxygen to form mercuric oxide

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What is the molar mass of CHC13?

suter [353]

Answer:119.38 g/mol

Explanation:

Add the Molar mass of each element to get the final answer. Use the Periodic table to find the molar mass. Molar mass is located under neath the elements.

7 0

3 years ago

Read 2 more answers

What’s the difference between chemical and nuclear energy?

Usimov [2.4K]

Answer:

nuclear is explosive and has potential energy while the other has kinetic energy

Explanation:

3 0

3 years ago

the ___is the area that allows us to pinpoint the location of pain, identify a texture and be aware of how our limbs are positio

vladimir1956 [14]

Answer:

The somatosensory cortex is a region of the brain which is responsible for receiving and processing sensory information from across the body, such as touch, temperature, and pain.

Area 1 specifically is important in sensing the texture of an object. :)

Hope this helps!

7 0

3 years ago

A women steps in front of a child to keep him from running off which term best describes this example

valina [46]

Negative force

The woman is applying force to stop the child or to prevent him from running.

I hope this helps...

4 0

3 years ago

Which of these half-reactions represents reduction?

gogolik [260]

Answer: The half-reactions represents reduction are as follows.

$Cr_{2}O^{2-}_{7} \rightarrow Cr^{3+}$
$MnO^{-}_{4} \rightarrow Mn^{2+}$

Explanation:

A half-reaction where addition of electrons take place or a reaction where decrease in oxidation state of an element takes place is called reduction-half reaction.

For example, the oxidation state of Cr in $Cr_{2}O^{2-}_{7}$ is +6 which is getting converted into +3, that is, decrease in oxidation state is taking place as follows.

$Cr_{2}O^{2-}_{7} + 3 e^{-} \rightarrow Cr^{3+}$

Similarly, oxidation state of Mn in $MnO^{-}_{4}$ is +7 which is getting converted into +2, that is, decrease in oxidation state is taking place as follows.

$MnO^{2-}_{4} + 5 e^{-} \rightarrow Mn^{2+}$

Thus, we can conclude that half-reactions represents reduction are as follows.

$Cr_{2}O^{2-}_{7} \rightarrow Cr^{3+}$
$MnO^{-}_{4} \rightarrow Mn^{2+}$

3 0

2 years ago