The electron pair geometry of a molecule is tetrahedral. What is its bond angle if it shows one lone pair of electrons and three
bonding pairs?
A) Less than 109.5°
B) More than 109.5°
C) Equal to 109.5°
D) Zero
A) Less than 109.5°
B) More than 109.5°
C) Equal to 109.5°
D) Zero
2 answers:
Answer: A) Less than 109.5°
Explanation: The electron pair geometry of a molecule is tetrahedral , which means the number of electrons is 4 that means the hybridization will be . and the bond angle will be 109.5°.
But as one lone pair of electrons and three bonding pairs are present, the fourth position will be occupied by lone pair of electrons. The repulsion between lone and bond pair of electrons is more and hence the bond angle will decrease from 109.5° and molecular geometry will be trigonal pyramidal.
As in ammonia molecule, the bond angle reduces to 107° due to the presence of lone pair of electron in tetrahedral geometry.
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<u>Answer:</u> The value of for the reaction is 6.32 and concentrations of
is 0.094 M, 0.094 M and 0.106 M respectively.
<u>Explanation:</u>
Relation of with
is given by the formula:
where,
= equilibrium constant in terms of partial pressure = 3.45
= equilibrium constant in terms of concentration = ?
R = Gas constant =
T = temperature = 500 K
= change in number of moles of gas particles =
Putting values in above equation, we get:
The equation used to calculate concentration of a solution is:
Initial moles of = 1.00 mol
Volume of the flask = 5.00 L
So,
For the given chemical reaction:
Initial: 0.2 - -
At Eqllm: 0.2 - x x x
The expression of for above reaction follows:
Putting values in above equation, we get:
Negative value of 'x' is neglected because initial concentration cannot be more than the given concentration
Calculating the concentration of reactants and products:
Hence, the value of for the reaction is 6.32 and concentrations of
is 0.094 M, 0.094 M and 0.106 M respectively.