Answer:
4. Force 1 Force 2 Comparison of Forces
Friction Gravity Force 1 is equal to Force 2
Explanation:
Answer:
713.51 N/m
Explanation:
Hook's Law: This law states that provided the elastic limit is not exceeded, the extension in an elastic material is directly proportional to the applied force.
From hook's law,
F = ke ...........................Equation 1
Where F = Force exerted on the bowstring, e = Extension/compression of the bowstring, k = Spring constant of the bow.
Make k the subject of the equation,
k = F/e ............................ Equation 2
Given: F = 264 N, e = 0.37 m.
Substitute into equation 2
k = 264/0.37
k = 713.51 N/m
Hence the spring constant of the bow = 713.51 N/m
Answer:Nuclear binding energy is the energy needed to separate nuclear particles
The strong nuclear force holds an atom’s protons and neutrons together
Nuclear binding energy can be calculated using E=mc2
Explanation:
I Think that the answer is 15.2096 Kilograms, but I might be wrong.
<h3>
Answer:</h3>
18.9 g F₂
<h3>
General Formulas and Concepts:</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Chemistry</u>
<u>Atomic Structure</u>
- Reading a Periodic Table
- Using Dimensional Analysis
- Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
3.00 × 10²³ molecules F₂
<u>Step 2: Identify Conversions</u>
Avogadro's Number
Molar Mass of F₂ (Diatomic) - 38.00 g/mol
<u>Step 3: Convert</u>
- Set up:

- Multiply:

<u>Step 4: Check</u>
<em>Follow sig fig rules and round. We are given 3 sig figs.</em>
18.9306 g F₂ ≈ 18.9 g F₂