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love history [14]
2 years ago
6

What forces create the bent triatomic shape of a water molecule

Chemistry
1 answer:
zimovet [89]2 years ago
4 0

Answer:

Repulsion Forces create the bent triatomic shape of a water molecule.

You might be interested in
Which type of hybridization is observed when central atom is located at the centre of regular tetrahedron
Ann [662]

Answer:

sp3 hybridization

Explanation:

Hybridization means the mixing of atomic orbitals to yield hybrid orbitals with characteristics that are different from that of the isolated atomic orbitals before the combination.

sp3 hybridization occurs when one s orbital is mixed with three p orbitals to yield four sp3 hybrid orbitals which can be used to bond to a central atom.

The central atom is then located at the center of a regular tetrahedron at a bond angle of 109°.

3 0
2 years ago
4. An 82 kg hiker climbs Mt. Humphrey near Flagstaff. During a two hour period, the hiker's
bazaltina [42]

Answer:

\Delta E = 434253.96\,J, \Delta P = 60.313\,W

Explanation:

The change in energy is given by the change in gravitational potential energy:

\Delta E = m\cdot g \cdot \Delta h

\Delta E = (82\,kg)\cdot (9.807\,\frac{m}{s^{2}} )\cdot (540\,m)

\Delta E = 434253.96\,J

The average rate of change in terms of time is approximately this:

\Delta P = \frac{\Delta E}{\Delta t}

\Delta P = \frac{434253.96\,J}{(2\,h)\cdot (\frac{3600\,s}{1\,h} )}

\Delta P = 60.313\,W

8 0
3 years ago
Using the Bohr model, determine the energy, in joules, necessary to ionize a ground-state hydrogen atom. Show your calculations.
lord [1]

Answer:

The energy required to ionize the ground-state hydrogen atom is 2.18 x 10^-18 J or 13.6 eV.

Explanation:

To find the energy required to ionize ground-state hydrogen atom first we calculate the wavelength of photon required for this operation.

It is given by Bohr's Theory as:

1/λ = Rh (1/n1² - 1/n2²)

where,

λ = wavelength of photon

n1 = initial state = 1 (ground-state of hydrogen)

n2 = final state = ∞ (since, electron goes far away from atom after ionization)

Rh = Rhydberg's Constant = 1.097 x 10^7 /m

Therefore,

1/λ = (1.097 x 10^7 /m)(1/1² - 1/∞²)

λ = 9.115 x 10^-8 m = 91.15 nm

Now, for energy (E) we know that:

E = hc/λ

where,

h = Plank's Constant = 6.625 x 10^-34 J.s

c = speed of light = 3 x 10^8 m/s

Therefore,

E = (6.625 x 10^-34 J.s)(3 x 10^8 m/s)/(9.115 x 10^-8 m)

<u>E = 2.18 x 10^-18 J</u>

E = (2.18 x 10^-18 J)(1 eV/1.6 x 10^-19 J)

<u>E = 13.6 eV</u>

5 0
3 years ago
100.mL of a .795 M solution of KBr is diluted to 500.mL. what is the new concentration of the solution?
kap26 [50]

Answer:

0.159 M

Explanation:

convert from mL to L then use the equation:

M1V1 = M2V2

rearrange to find M2

\frac{M1V1}{V2} = M2

\frac{(0.795 M)(0.100 L)}{0.500 L} = 0.159 M

4 0
2 years ago
What are the charges and relative masses of the 3 main subatomic particles
blondinia [14]
Proton: positive- mass equal to neutron
Electron: negative- mass 1/1840 mass of proton 
Neutron: no charge- same mass as proton
5 0
3 years ago
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