Answer:
low amplitude hope it will help you
Answer:
Hey mate
Your answer will be <u>5 N</u><u> </u><u>Upwards</u><u>.</u><u> </u>
I will explain this to you.
In the attachment we can see that there are two forces acting on the object from the same side. And we know that when force acts from the same direction. Then the total force
=> sum of all the forces in that particular direction.
I hope you got it :)
TheSarcasmic
Answer:
1.736m/s²
Explanation:
According to Newton's second law;

where;
Fm is the moving force = 70.0N
Ff is the frictional force acting on the body

is the coefficient of friction
m is the mass of the object
g is the acceleration due to gravity
a is the acceleration/deceleration
The equation becomes;

Substitute the given parameters

Hence the deceleration rate of the wagon as it is caught is 1.736m/s²
Answer:
a

b

Explanation:
Generally the force of attraction between this two irons is mathematically represented as
![F = \frac{k * [Q_{Li} ] * [Q_{O} ] }{ r^2}](https://tex.z-dn.net/?f=F%20%3D%20%20%5Cfrac%7Bk%20%2A%20%20%5BQ_%7BLi%7D%20%20%5D%20%2A%20%5BQ_%7BO%7D%20%20%5D%20%20%7D%7B%20r%5E2%7D)
Here k is known as the proportionality constant with value 
substituting -2 for
i.e the charge on oxygen , +1 for
i.e the charge on Lithium and
for r
So


Generally the force of repulsion will be the magnitude but different direction to the force o attraction
So Force of repulsionn is

Hey there!
Seems like you're looking for the size and direction to the final velocity of the two cars. To find it, you must solve it like this.
0.4 kg(3 m/s) + 0.8kg(–2 m/s) = 1.2 kg m/s -1.6 kg m/s = –0.4 kg m/s
–0.4 kg m/s = 1.2 kg(v) = (–0.4 kg m/s)/(1.2 kg) = v = –0.33 m/s
So, the cars are traveling at -0.33 m/s in the direction of the second car.
Hope this helps
<em>Tobey</em>