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3 years ago

13

What property of most stars can be determined by their color?

1 answer:

just olya [345]3 years ago

4 0

I think it’s luminosity. I really hope it’s right and helped you.

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A hiker leaves her camp and walks 3.5 km in a direction of 55° south of west to the lake. after a short rest at the lake, she hi

3241004551 [841]

Let's choose east as positive x-direction and south as positive y-direction. We can resolve the two displacement along these two axes:

- Displacement 1 (3.5 km, $55^{\circ}$ south of west

$d_{1x}=-(3.5 km)( cos 55^{\circ})=-2.01 km$

$d_{1y}=(3.5 km)( sin 55^{\circ})=2.87 km$

- Displacement 2 (2.7 km, $16^{\circ}$ east of south

$d_{2x}=(2.7 km)( sin 16^{\circ})=0.74 km$

$d_{1y}=(2.7 km)( cos 16^{\circ})=2.60 km$

So, the total components on the two directions are

$d_x = -2.01 km+0.74 km=-1.27 km$

$d_y=2.87 km+2.60 km=5.47 km$

And the magnitude of the hiker's resultant displacement is

$d=\sqrt{(1.27 km)^2+(5.47 km)^2}=5.6 km$

8 0

3 years ago

Read 2 more answers

Which month has the longest day and shortest night?

Volgvan

I think it’s June 20

8 0

2 years ago

A proton moves with a velocity of v with arrow = (3î − 5ĵ + k) m/s in a region in which the magnetic field is B with arrow = (î

Allisa [31]

Answer:

The magnitude of the magnetic force this particle experiences is $2.6\times10^{-9}\ N$ .

Explanation:

Given that,

Velocity v= (3i-5j+k) m/s

Magnetic field B=(i+2j-k) T

We need to calculate the value $\vec{v}\times\vec{B}$

$(\vec{v}\times\vec{B})=3i+4j+11k$

We need to calculate the magnitude of the magnetic force this particle experiences

Using formula of magnetic force

$\vec{F}=q(\vec{v}\times\vec{B})$

Put the value into the formula

$\vec{F}=1.6\times10^{-19}\times(3i+4j+11k)$

$\vec{F}=(4.8i+6.4j+1.76k)\times10^{-19}$

$|F|=2.6\times10^{-9}\ N$

Hence, The magnitude of the magnetic force this particle experiences is $2.6\times10^{-9}\ N$ .

7 0

2 years ago

A spherical shell contains three charged objects. The first and second objects have a charge of − 14.0 nC and 33.0 nC , respecti

matrenka [14]

Explanation:

Formula depicting relation between total flux and total charge Q is as follows.

$\phi = \frac{Q}{\epsilon_{o}}$ (Gauss's Law)

Putting the given values into the above formula as follows.

Q = $\phi \times \epsilon_{o}$

= $-953 Nm^{2}/C \times 8.854 \times 10^{-12}$

= $-8.4 \times 10^{-9} C$

= -8.4 nC

Therefore, when the unknown charge is q then,

-14.0 nC + 33.0 nC + q = -8.4 nC

q = -27.4 nC

Thus, we can conclude that charge on the third object is -27.4 nC.

7 0

3 years ago

"Which of the following is true about the atom shown? Choose all that apply.

aalyn [17]

Option B & Option D is your correct answers.

'cause here, atom has eight electrons in it's valence shell, so it means it has stable structure which falls in group 18

Hope this helps!

8 0

2 years ago

Read 2 more answers