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nadezda [96]
2 years ago
13

Suppose the velocity of an object moving along a line is positive. are position, displacement, and distance traveled equal? expl

ain. my math lab
Physics
1 answer:
Pavlova-9 [17]2 years ago
4 0

No, the object's displacement and distance travelled will be equal, but since the initial position is unknown, the object's position might not match up with its displacement and distance travelled.

We cannot assert that the displacement or distance equals the position because the initial position is not provided. We could reach a different conclusion if the starting position had been zero because the distance from zero is equal to the position.

Find more on velocity at : brainly.com/question/11347225

#SPJ4

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Trying to beat the heat of the last summer, a physics grad student went to the local toy store and purchased a plastic child's s
svp [43]

Answer:

625 piece.

Explanation:

Let n be the required no of piece

200 litre = 200 x 10⁻³ m³ = 200 x 10⁻³ x 10³ kg = 200 Kg

mass of ice piece =  n x 30 x /1000

Heat lost by ice pieces  = (n x 30) / 1000 x  ( 80 + 1 x 16⁰C)

Heat gained by water = 200 x 1 x 9⁰C

Heat lost  = Heat gained

(n x 30) /1000 x ( 80 + 16 ) =200 x 9

2.88 n = 1800

n = 625

6 0
4 years ago
What happens to the radiation coming from the Sun and heading towards Earth?
miss Akunina [59]

Answer: some of the energy are shielded away by the ozone layer,

The rest warm the earth

Explanation:

Not all energy from the sun reaches the earth, some of the energy are shielded away by the ozone layer while the rest energy warm the earth

7 0
3 years ago
Does the thickness of the wire affect the strength of an electroscope
TiliK225 [7]
It probably does. I'm not 100% sure about it, but a thicker wire would increase the number of positive and negative charges in it.
4 0
3 years ago
A compact disc (CD) is played by a cd player, which uses a laser to read the tracks on the disc. The disc spins initially at app
uranmaximum [27]

Answer:

a. The laser tracking mechanism experiences a changing tangential velocity

c. The laser tracking mechanism experiences a non-zero angular acceleration

d. The laser tracking mechanism experiences a non-zero tangential acceleration

Explanation:

a. The laser tracking mechanism experiences a changing tangential velocity

This is because the tangential velocity v = rω where r = radius of disc and ω  = angular speed of discs. Since r is constant, v ∝ ω.

Since the angular speed changes from 200 rpm to 500 rpm, thus, the tangential velocity would also change.

So, the laser tracking mechanism experiences a changing tangential velocity

c. The laser tracking mechanism experiences a non-zero angular acceleration

Since angular acceleration, α = Δω/Δt where Δω = change in angular speed and Δt = change in time.

Since there is a change in angular speed from 200 rpm to 500 rpm in time Δt, there is thus a non-zero angular acceleration.

So, The laser tracking mechanism experiences a non-zero angular acceleration

d. The laser tracking mechanism experiences a non-zero tangential acceleration

Since tangential acceleration, a = rα where r = radius of disc and α = angular acceleration.

Since there is an angular acceleration of the disc, there is thus going to be a tangential acceleration given by a = rα.

So, the laser tracking mechanism experiences a non-zero tangential acceleration

Statement b is false because, the disc experiences a changing angular speed from 200 rpm to 500 rpm.

4 0
3 years ago
If R1 = 6, R2 = 2 and VAΓ = 16 Find Roλ, I, VAB, VAΓ​
erica [24]

Answer:

<em>Rt = 8 ohm</em>

<em>I = 2 A</em>

<em>Vab = 12 V</em>

<em>VbΓ = 4 V</em>

<em>VaΓ = 16 V</em>

Explanation:

<u>Electric Circuits</u>

We'll apply Ohm's formula to solve the circuit shown on the image:

V = R.I

Where V is the voltage, R is the resistance, and I is the current.

The circuit has two resistances connected in series, thus the total resistance is:

Rt = R1 + R2 = 6 ohm + 2 ohm = 8 ohm

Now the current is:

\displaystyle I=\frac{V}{Rt}

\displaystyle I=\frac{16}{8}

I = 2 A

The voltages are calculated below:

Vab = R1 * I = 6 ohm * 2 A = 12 V

VbΓ = R2 * I = 2 ohm * 2 A = 4 V

VaΓ = Vab + VbΓ = 12 V + 4 V = 16 V

8 0
3 years ago
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