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Veseljchak [2.6K]
3 years ago
6

A force vector F1 points due east and has a magnitude of 200N. A second force F2 is added to F1. The resultant of the two vector

s has a magnitude of 400N and points along the east/west line. Find the magnitude and direction of F2Source https://www.physicsforums.com/threads/physics-trigonometry.61160/
Physics
1 answer:
PilotLPTM [1.2K]3 years ago
3 0

Answer:

The second vector \vec{F_2} points due West with a magnitude of 600N

Explanation:

The original vector \vec{F_1} points with a magnitude of 200N due east, the Resultant vector \vec{R} points due west (that's how east/west direction can be interpreted, from east to west) with a magnitude of  400N. If we choose East as the positive direction and West as the negative one, we can write the following vectorial equation:

\vec{F_1}+\vec{F_2}=\vec{R}\implies\vec{F_2}=\vec{R}-\vec{F_1}=-400N-200N=-600N

With the negative sign signifying that the vector points west.

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