Answer:
300 centavos
Explanation:
De la pregunta anterior, se obtuvieron los siguientes datos:
Potencia (P) = 2500 W
Tiempo (t) = 8 horas
Costo de operación =?
A continuación, convertiremos 2500 W a KW. Esto se puede obtener de la siguiente manera:
1000 W = 1 KW
Por lo tanto,
2500 W = 2500 W × 1 KW / 1000 W
2500 W = 2,5 KW
Por tanto, 2500 W equivalen a 2,5 KW
A continuación, determinaremos la energía consumida. Esto se puede obtener de la siguiente manera: Potencia (P) = 2,5 KW
Tiempo (t) = 8 horas
Energía (E) =?
E = Pt
E = 2,5 × 8
E = 20 KWh
Finalmente, determinaremos el costo de operación. Esto se puede obtener de la siguiente manera:
1 KWh = 15 centavos
Por lo tanto,
20 KWh = 20 KWh × 15 centavos / 1 KWh
20 KWh = 300 centavos
Por lo tanto, costará 300 centavos tener un radiador de 2500 W encendido toda la noche (8 horas).
Moles CO = 10.0 g / 28.01 g/mol = 0.357
<span>the ratio between CO and CO2 is 2 : 2 ( or 1 : 1) so we would get 0.357 mole of CO2 ( 100% yield) </span>
<span>mass CO2 = 0.357 mol x 44.0098 g/mol = 15.7 g ( theoretical yield) </span>
<span>% yield = 12.8 x 100 / 15.7 = 81.5
Hope this helps.</span>
<span>Answer:
Glass has a much higher specific heat than styrofoam so more of the energy produced will go into heating the glass. This quantity of heat will be lost (unaccounted for) hence the delta t in the calculation will be too small and the heat of neutralization will be lower.</span>
If 1000 ml (1 L) of CH₃COOH contain 1.25 mol
let 250 ml of CH₃COOH contain x
⇒ x =
= 0.3125 mol
∴ moles of CH₃COOH in 250ml is 0.3125 mol
Now, Mass = mole × molar mass
= 0.3125 mol × [(12 × 2)+(16 × 2)+(1 × 4)] g/mol
= 18.75 g
∴ Mass of CH₃COOH present in a 250 mL cup of 1.25 mol/L solution of vinegar is <span>18.75 g</span>
Answer:
22.54 moles of NaBr are needed
Explanation:
The reaction of Cl2 with NaBr occurs as follows:
Cl2 + 2NaBr → 2NaCl + Br2
<em>Where 1 mole of Cl2 requires 2 moles of NaBr for a complete reaction</em>
<em />
As in the problem, we have 11.27 moles of Cl2, the moles of NaBr required are:
11.27mol Cl2 * (2mol NaBr / 1mol Br2) =
<h3>22.54 moles of NaBr are needed</h3>