If there are 10.0g of sucrose and 8.0 of oxygen, how many moles of sucrose are available for this reaction?

A gas cylinder initially contains 463 L of gas at a pressure of 159 atm. If the final volume of gas is 817 L, what is the final

Agata [3.3K]

Answer:

The final pressure is 90.1 atm.

Explanation:

Assuming constant temperature, we can solve this problem by using Boyle's Law, which states:

P₁V₁=P₂V₂

Where in this case:

P₁ = 159 atm

V₁ = 463 L

P₂ = ?

V₂ = 817 L

We input the given data:

159 atm * 463 L = P₂ * 817 L

And solve for P₂:

P₂ = 90.1 atm

The final pressure is 90.1 atm.

6 0

3 years ago

A 1.000-g sample of lead shot reacted with oxygen to give 1.077 g of product. Calculate the empirical formula of the lead oxide

Evgesh-ka [11]

It mean it consisted of 1 g of lead and 0.077 g of O2.
divide these numbers by molar mas.
1/82=0.012 Pb /0.004 = 3
0.077/16= 0.004 O /0.004 =1
Pb3O

3 0

3 years ago

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Antimony has two naturally occuring isotopes, 121 Sb and 123 Sb . 121 Sb has an atomic mass of 120.9038 u , and 123 Sb has an at

valina [46]

Answer:

Percentage abundance of 121 Sb is = 57.2 %

Percentage abundance of 123 Sb is = 42.8 %

Explanation:

The formula for the calculation of the average atomic mass is:

$Average\ atomic\ mass=(\frac {\%\ of\ the\ first\ isotope}{100}\times {Mass\ of\ the\ first\ isotope})+(\frac {\%\ of\ the\ second\ isotope}{100}\times {Mass\ of\ the\ second\ isotope})$

Given that:

Since the element has only 2 isotopes, so the let the percentage of first be x and the second is 100 -x.

For first isotope, 121 Sb :

% = x %

Mass = 120.9038 u

For second isotope, 123 Sb:

% = 100 - x

Mass = 122.9042 u

Given, Average Mass = 121.7601 u

Thus,

$121.7601=\frac{x}{100}\times 120.9038+\frac{100-x}{100}\times 122.9042$

$120.9038x+122.9042\left(100-x\right)=12176.01$

Solving for x, we get that:

x = 57.2 %

Thus, percentage abundance of 121 Sb is = 57.2 %

percentage abundance of 123 Sb is = 100 - 57.2 % = 42.8 %

6 0

3 years ago

True or False, Atoms with fewer then 4 outer electrons lend electrons

hammer [34]

Answer:

true

I think please thanks

6 0

2 years ago

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What happens to the rate of a reaction as the reaction progresses?

ZanzabumX [31]

Answer:

D. The rate decreases as reactants are used up.

Explanation:

Initially, the rate increases until the reaction is at equilibrium. At equilibrium, the rate is constant.

As the reaction progresses, the rate decreases to zero when reactants are used up ( for irriversible reactions only )

3 0

3 years ago

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