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muminat
3 years ago
10

If there are 10.0g of sucrose and 8.0 of oxygen, how many moles of sucrose are available for this reaction?

Chemistry
1 answer:
nordsb [41]3 years ago
8 0
0.029 is the correct answer
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How many electrons are in p orbitals in Si (Silicon)?
insens350 [35]

Answer:

6 electrons

Explanation:

The p orbital can hold up to six electrons. We'll put six in the 2p orbital and then put the next two electrons in the 3s.

8 0
3 years ago
What is the mass of 0.28 mole of iron?
vredina [299]

Answer:

Your answer should be 15.68 grams.

Explanation:

Seeing as 1 mole has a mass of 56 g, 56*0.28 would get you 15.68 g.

6 0
3 years ago
Which nuclide is most likely to be radioactive and synthetic
White raven [17]

Answer:

237/93 np

Explanation:

sub to tkwick

7 0
3 years ago
13. A mixture of MgCO3 and MgCO3.3H2O has a mass of 3.883 g. After heating to drive off all the water the mass is 2.927 g. What
rjkz [21]

Answer:

63.05% of MgCO3.3H2O by mass

Explanation:

<em>of MgCO3.3H2O in the mixture?</em>

The difference in masses after heating the mixture = Mass of water. With the mass of water we can find its moles and the moles and mass of MgCO3.3H2O to find the mass percent as follows:

<em>Mass water:</em>

3.883g - 2.927g = 0.956g water

<em>Moles water -18.01g/mol-</em>

0.956g water * (1mol/18.01g) = 0.05308 moles H2O.

<em>Moles MgCO3.3H2O:</em>

0.05308 moles H2O * (1mol MgCO3.3H2O / 3mol H2O) =

0.01769 moles MgCO3.3H2O

<em>Mass MgCO3.3H2O -Molar mass: 138.3597g/mol-</em>

0.01769 moles MgCO3.3H2O * (138.3597g/mol) = 2.448g MgCO3.3H2O

<em>Mass percent:</em>

2.448g MgCO3.3H2O / 3.883g Mixture * 100 =

<h3>63.05% of MgCO3.3H2O by mass</h3>
6 0
3 years ago
Help please, how are the electrons and bonds represented in a lewis dot diagram?
Lapatulllka [165]

Answer:

Lewis dot diagrams use dots arranged around the atomic symbol to represent the electrons in the outermost energy level of an atom

Explanation:

6 0
3 years ago
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