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ohaa [14]
3 years ago
5

The circumference of mars is about 10,664km. Find the diameter of mars to

Mathematics
2 answers:
Rom4ik [11]3 years ago
4 0

3,396 km

hope this helps

umka2103 [35]3 years ago
3 0
Diameter of mars near to the 3396 km
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I believe 18 is the correct answer.
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Compare the following functions: f(x) = 3 sin(x − π) + 4 g(x) graph of a quadratic with points at 1, 5 and 3, 1 and 5, 5 h(x) x
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Answer:

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Step-by-step explanation:

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Compare the weather on two different days using an inequality. Then see if their comparisons change by finding the absolute valu
dusya [7]

Inequalities are used to compare unequal expressions.

The actual comparison is:\mathbf{-3.5 < 5} or \mathbf{5 > -3.5}

The temperatures are given as:

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\mathbf{-3.5 < 5} or \mathbf{5 > -3.5}

Using absolute values, the inequalities are:

\mathbf{|-3.5| < |5|} or \mathbf{|5| > |-3.5|}

Hence, the actual comparison is:

\mathbf{-3.5 < 5} or \mathbf{5 > -3.5}

Read more about inequalities and absolute values at:

brainly.com/question/24797699

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3 years ago
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The domain of both f(x) = x - 6 and g(x) = x + 6 is all real numbers. What is the domain of h(x) = f(x)/g(x)?
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This is a quotient (division) of two functions we must be concerned with the fact that division by zero is undefined.

Since g(x) is in the divisor position, it cannot equal 0.
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Set notation {x | x ∈ R, x ≠ -6}
Interval notation (-∞,-6)∪(-6,∞)
6 0
3 years ago
Please help with #6. How do I find all of the real zeros? Thank you!!!
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I'm assuming you're referring to problem 6. You are asked to find the number of x intercepts or roots, which is another term for "zero". I prefer the term root or x intercept as "zero" seems misleading. Anyways, all we do is count the number of times the graph crosses the x axis. This happens 4 times as shown in the attached image below. I have marked these points in red. The graph can directly cross over the x axis, or it can touch the x axis and then bounce back. Either way, it is considered an x intercept.

<h3>Answer: there are 4 x intercepts (or 4 roots)</h3>

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