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Darina [25.2K]
3 years ago
8

HELP ME PLEASE!!! 2(b+3)-(7+b)=-7 ??

Mathematics
2 answers:
Effectus [21]3 years ago
6 0

<u>To solve this first distribute the 2, and then distribute the negative sign.</u>

2(b+3)-(7+b)=-7

2b+6-7-b=-7

<u>Combine like terms.</u>

2b+(-b)=b

6+(-7)=-1

b-1=-7

<u>Add 1 on both sides of the equation.</u>

b-1+1=-7+1

b=-6

Natasha2012 [34]3 years ago
4 0

2(b + 3) - (7 + b) = -7

2b + 6 - 7 - b = -7

b = -6 + 7 - 7

b = -6

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Identify the slope and the y-intercept
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Plot the point corresponding to the y-intercept, (0,1)
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And once you have your second point you can just draw a line through the two points and extend it in both directions.
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You can check to see that the line you've drawn is the correct one by substituting the coordinates of the second point into the original equation. If the equation holds true than the second point is correct.
Our second point = (1, 3)
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4 0
3 years ago
Thank you for the help! I would appreciate it if someone could explain this content to me. I need help on both of them. I wish t
maksim [4K]
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5 0
2 years ago
Does anyone know this?
barxatty [35]

Answer:

\Huge \boxed{-2}

Step-by-step explanation:

f(x)=-2x^2-2x+10

For f(2), the input of the function is 2.

Let x = 2.

f(2)=-2(2)^2-2(2)+10

Evaluate.

f(2)=-2(4)-2(2)+10

f(2)=-8-4+10

f(2)=-2

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3 years ago
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Ghella [55]
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3 years ago
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2x^2 + 3x - 12 when x = 5 help pls
cluponka [151]

\huge\textsf{Hey there!}

\mathsf{2x^2 + 3x - 12}

\mathsf{= 2(5)^2 + 3(5) - 12}

\mathsf{5^2}

\mathsf{= 5 \times 5}

\mathsf{\bf = 25}

\mathsf{2(25) + 3(5) - 12}

\mathsf{2(25)}

\mathsf{= \bf 50}

\mathsf{3(5)}

\mathsf{= \bf 15}

\mathsf{= 50 + 15 -  12}

\mathsf{50 + 15}

\mathsf{= \bf 65}

65 - 12

\mathsf{= \bf 53}

\boxed{\boxed{\huge\textsf{Answer: \bf 53}}}\huge\checkmark

\large\textsf{Good luck on your assignment and enjoy your day!}

~\frak{Amphitrite1040:)}

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2 years ago
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