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Anuta_ua [19.1K]
3 years ago
10

For a quantity of gas at a constant temperature, the pressure P is inversely proportional to the volume V. What is the limit of

P as V approaches 0 from the right? Explain what this means in the context of the problem.
Physics
1 answer:
IceJOKER [234]3 years ago
7 0

Answer:

lim_{V \to 0^{+}} P = k\lim_{V \to 0^{+}} \frac{1}{V} =\infty

This limit is not defined.

Explanation:

We need to remember first this law

The Boyle's law states that under a constant temperature when the pressure is inversely proportion to the volume.

So that means: P \propto \frac{1}{V}

And we can put an equal if we do this:

P = \frac{k}{V} where k is the proportional constant.

For this case we want to find the following limit:

lim_{V \to 0^{+}} P = \lim_{V \to 0^{+}} \frac{k}{V}

And using properties of limits we have:

lim_{V \to 0^{+}} P = k\lim_{V \to 0^{+}} \frac{1}{V}

So for this case this limit tend to infinity since we are dividing a constant by a very low number positive near to 0.

So then we can conclude that:

lim_{V \to 0^{+}} P = k\lim_{V \to 0^{+}} \frac{1}{V} =\infty

This limit is not defined.

Interpretation: we are seeing that if the volume decrease considerable with the temperature constant by the inverse relation between P and V, the value of P increases to with no limit.

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wel

Answer:

100°c = 373.15 K

100°C=212°F

Explanation:

  • Given the 100°C

To convert Celsius to Kelvin, we need the following equation.

°C + 273.15 = K

100°C + 273.15 = K

373.15 = K

Therefore, 100°c = 373.15 K

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F = 9/5C + 32

   =9/5(100)+32

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Answer:

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Explanation:

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Area of square, A=a^2=(0.305)^2=0.0930\ m^2

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A'=\pi r^2\\A'=\pi (0.194)^2\\\\A'=0.118\ m^2

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means
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