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Anuta_ua [19.1K]
3 years ago
10

For a quantity of gas at a constant temperature, the pressure P is inversely proportional to the volume V. What is the limit of

P as V approaches 0 from the right? Explain what this means in the context of the problem.
Physics
1 answer:
IceJOKER [234]3 years ago
7 0

Answer:

lim_{V \to 0^{+}} P = k\lim_{V \to 0^{+}} \frac{1}{V} =\infty

This limit is not defined.

Explanation:

We need to remember first this law

The Boyle's law states that under a constant temperature when the pressure is inversely proportion to the volume.

So that means: P \propto \frac{1}{V}

And we can put an equal if we do this:

P = \frac{k}{V} where k is the proportional constant.

For this case we want to find the following limit:

lim_{V \to 0^{+}} P = \lim_{V \to 0^{+}} \frac{k}{V}

And using properties of limits we have:

lim_{V \to 0^{+}} P = k\lim_{V \to 0^{+}} \frac{1}{V}

So for this case this limit tend to infinity since we are dividing a constant by a very low number positive near to 0.

So then we can conclude that:

lim_{V \to 0^{+}} P = k\lim_{V \to 0^{+}} \frac{1}{V} =\infty

This limit is not defined.

Interpretation: we are seeing that if the volume decrease considerable with the temperature constant by the inverse relation between P and V, the value of P increases to with no limit.

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3 years ago
Most automobiles have a coolant reservoir to catch radiator fluid that may overflow when the engine is hot. A radiator is made o
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Answer:

There is a loss of fluid in the  container of 0.475L

Explanation:

To solve the problem it is necessary to take into account the concepts related to the change of voumen in a substance depending on the temperature.

The formula that describes this thermal expansion process is given by:

\Delta V = \beta V_0 \Delta T

Where,

\Delta V =Change in volume

V_0 =Initial Volume

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\beta = coefficient of volume expansion (Coefficient of copper and of the liquid for this case)

There are two types of materials in the container, liquid and copper, so we have to change the amount of Total Volume that would be subject to,

\Delta V_T = \Delta V_l - \Delta V_c

Where,

\Delta V_l= Change in the volume of liquid

\Delta V_c= Change in the volume of copper

Then replacing with the previous equation we have:

\Delta V = \beta_l V_0 \Delta T- \beta_c V_0 \Delta T

\Delta V = (\beta_l-\beta_c)V_0\Delta T

Our values are given as,

Thermal expansion coefficient for copper and the liquid to 20°C is

\beta_c = 51*10^{-6}/\°C

\beta_l = 400*10^{-6}/\°C

V_0 = 16L

\Delta T = (95\°C-10\°C)

Replacing we have that,

\Delta V = (\beta_l-\beta_c)V_0\Delta T

\Delta V = (400*10^{-6}/\°C-51*10^{-6}/\°C)(16L)(95\°C-10\°C)

\Delta V = 0.475L

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3 years ago
What is the range of motion of the elbow if extension is 0° and flexion is 145°?
inna [77]

Answer:

0 to 145 degrees

Explanation:

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2 years ago
A solid block is attached to a spring scale. When the block is suspended in air, the scale reads 21.2 N; when it is completely i
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Answer:

7066kg/m³

Explanation:

The forces in these cases (air and water) are: Fa =mg =ρbVg Fw =(ρb −ρw)Vg where ρw = 1000 kg/m3 is density of water and ρb is density of the block and V is its density. We can find it from this two equations:

Fa /Fw = ρb / (ρb −ρw) ρb = ρw (Fa /Fa −Fw) =1000·(1* 21.2 /21.2 − 18.2)

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Explanation:

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