On that system is In an isolated system, the net __ zero.
1 answer:
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Answer:
(a). The blood travel during this acceleration is 0.0231 m.
(b). The time for the blood to reach its peak speed is 0.0459 sec.
Explanation:
Given that,
Acceleration = 22.0 m/s²
Speed = 1.01 m/s
(a). We need to calculate the distance
Using equation of motion
Where, v = final speed
u = initial speed
a = acceleration
s = distance
Put the value into the formula
(b). We need to calculate the time
Using equation of motion
Put the value into the formula
Hence, (a). The blood travel during this acceleration is 0.0231 m.
(b). The time for the blood to reach its peak speed is 0.0459 sec.
Answer:
μ = tan θ
Explanation:
For this exercise let's use the translational equilibrium condition.
Let's set a datum with the x axis parallel to the plane and the y axis perpendicular to the plane.
Let's break down the weight of the block
sin θ = Wₓ / W
cos θ = W_y / W
Wₓ = W sin θ
W_y = W cos θ
The acrobat is vertically so his weight decomposition is
sin θ = = wₐₓ / wₐ
cos θ = wₐ_y / wₐ
wₐₓ = wₐ sin θ
wₐ_y = wₐ cos θ
let's write the equilibrium equations
Y axis
N- W_y - wₐ_y = 0
N = W cos θ + wₐ cos θ
X axis
Wₓ + wₐ_x - fr = 0
fr = W sin θ + wₐ sin θ
the friction force has the formula
fr = μ N
fr = μ (W cos θ + wₐ cos θ)
we substitute
μ (Mg cos θ + mg cos θ) = Mgsin θ + mg sin θ
μ =
μ = tan θ
this is the minimum value of the coefficient of static friction for which the system is in equilibrium.