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Mekhanik [1.2K]
3 years ago
9

Pam Jones worked for 41 years at the same company and had positive performance ratings and personnel records. She needed a calcu

lator for work which she purchased with her own money but was not reimbursed because she lost the receipt. Later, a security guard stopped her as she was leaving work and discovered the calculator in her belongings. After a brief internal investigation, she was fired and it was announced through internal notices that she had committed a theft. The employee sued for libel, saying the company used her as an example to prevent other thefts.a) What are the key issues in this case?b) As an HR Director, how would you have handled this case?
Engineering
1 answer:
UNO [17]3 years ago
5 0

Answer:

a) The key issues are the sue for libel and the evidence.

b) I would make a deal with her and implement a security program in the company.

Explanation:

The main issue in this case is that Pam Jones sued the company for libel, and the company remains in a position in which it has to prove that the internal investigation followed the right steps and indeed, the proves reflected that she was guilty and the fact that she got fired was correct.

The important here is exactly that the theft can be proved.

As an HR Director, I would give the correct proves in order to win the case, and if that is impossible, because of the tools and evidence, I would make a deal with her where both parts can be adequate to the problem.

She can´t be working again in the company but she can get financed according to her working years; also I would use this case as a growing opportunity by implementing new security methods that give more confidence between the company and its employees.

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A solid steel shaft has to transmit 100 kW at 160 RPM. Taking allowable shear stress at 70 Mpa, find the suitable diameter of th
MA_775_DIABLO [31]

Answer:

The diameter of the shaft is 80.5 mm.

Explanation:

Torsion equation is applied for the diameter of the solid shaft.

Step1

Given:

Power of the shaft is 100 kw.

Revolution per minute is 160 RPM.

Allowable shear stress is 70 Mpa.

Maximum torque is 20% more than the mean torque.  

Step2

Mean torque is calculated as follows:

P=T\omega

P=T(\frac{2\pi N}{60})

100\times 1000=T(\frac{2\pi 160}{60})

T=5968.31 N-m

Step3

Maximum torque is calculated as follows:

T_{max}=(1+\frac{20}{100})T

T_{max}=1.2T

T_{max}=1.2\times 5968.31

T_{max}=7161.97 N-m

Step4

Apply torsional equation for diameter of shaft as follows:

\tau _{max}=\frac{T_{max}}{\frac{\pi d^{3}}{16}}

70\times 10^{6}=\frac{7161.97}{\frac{\pi d^{3}}{16}}

d^{3}=5.211\times 10^{-4}

d=0.0805 m

or,

d=80.5 mm

Thus, the diameter of the shaft is 80.5 mm.

7 0
3 years ago
For a metal casting with a cylindrical riser, what is the best (optimal) aspect ratio (aspect ratio is the ratio of the riser's
DochEvi [55]

Answer:

Optimal aspect ratio = 1

Explanation:

From Chvorinov's Rule,

T = c [\frac{volume}{surface are}]^n

Where

T = solidification time

c = mold constant

Volume = \frac{pi D^2 h}{4}

Surface areaA= pi Dh[\frac{2pi D^2}{4}

For the riser to have the longest solidification time:

We have: D = h

V = \frac{pi D^3}{4}

A = pi Dh[\frac{2pi D^2}{4}] = 1.5D^2 pi

Therefore,

\frac{V}{A} = \frac{\frac{pi D^3}{4}}{1.5D^2 pi}

\frac{V}{A} = \frac{D}{6}

To have to longest solidification time, D = h

Therefore the best aspect ratio would be,

\frac{D}{h} = 1

3 0
3 years ago
Why is Ethics an important part of engineering?
NemiM [27]

Answer:

Products created can change society, for better and for the worse

It was damaged in a fire

8 0
3 years ago
Consider the simplicity of these two DOE examples. Next, consider the assertion that DOE isn’t put into practice as often or dee
Bingel [31]

Answer:

Do Re Mi

Explanation:

I have no clue sorry

5 0
3 years ago
Some aircraft component is fabricated from an aluminum alloy that has a plane strain fracture toughness of 35 MPa m . It has bee
GaryK [48]

Answer:  Fracture will not occur since Kc (32.2 MPa√m) ∠ KIc (35  MPa√m).

Explanation:

in this question we are asked to determine if an aircraft will fracture for a given fracture toughness.

let us begin,

from the question we have that;

stress = 325 MPa

fracture toughness (KIc) = 35  MPa√m

the max internal crack length = 1.0 m

using the formula;

Y = KIc/σ√(πα)    ---------------(1)

solving for Y we have;

Y =  35 (MPa√m) / 250 (MPa) √(π × 2×10⁻3/2m)

Y = 2.50

so to calculate the fracture roughness;

Kc = Y × σ√(πα)   = 2.5 × 3.25√(π × 1×10⁻³/2) = 32.2 MPa√m

Kc = 32.2 MPa√m

From our results we can say that fracture will not occur since Kc (32.2 MPa√m) is less than KIc (35  MPa√m) of the material.

cheers i hope this helps!!!!

8 0
3 years ago
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