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xxMikexx [17]
3 years ago
15

U 4. Find 2 bridges in the US and answer the following:

Engineering
1 answer:
Zarrin [17]3 years ago
6 0

Answer:

Im guessing this is for CEA for PLTW, if so look up the exact assignment number and look at online examples of the exact same assignment.

Explanation:

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While you are driving you see an animal standing or walking on the side of the road. You should..
STatiana [176]
Take caution, and slow down, it could run out in the middle of the road. Try going around it if possible.
8 0
3 years ago
Is it a problem that the stress intensity factor, K, from Irwin's near-tip approximation approaches infinity as you get close to
valina [46]

Answer:

No it is not a problem

Explanation:

It is not a problem because the stress intensity factor K would approach infinity as you get close to a crack tip and the intensity factor would approach Zero as you get too far away from the crack tip and this is simply because a crack is a notch with zero tip radius .

and The application of stress intensity factor k in respect to present fatigue crack tip is termed " linear elastic fracture mechanics "

3 0
3 years ago
You and your design group are competing for a multidisciplinary concept project. Your firm is the lead group in the design profe
sasho [114]

Answer: the answer for the question is a

Explanation:

4 0
3 years ago
What information is usually gathered during vehicle crash tests?
aleksley [76]
Time, distance, damage
7 0
3 years ago
a turbine operating at steady state at 500 kPa, 860 K and exists at 100 kPa. A temperature sensor indicates that the exit air te
noname [10]

Answer:

Given:

P₁ = 500 kPa

T₁ = 860 K

P₂= 100 kPa

T₂ = 460 K

Let's take entropy properties of T1 and T2 from ideal properties of air,

at T = 860K, s(T₁) = 2.79783 kJ/kg.K

at T = 460K, s(T₂) = 2.13407 kJ/kg.K

using entropy balance equation:

\frac{\sigma _cv}{m} = s(T_2)- s(T_1) - R In [\frac{P_2}{P_1}]

\frac{\sigma _cv}{m} = 2.79783 - 2.13407 - 0.287 In [\frac{100}{500}]

= - 0.2018 kJ/kg. K

In this case the entropy is negative, which means the value of exit temperature is not correct, beacause entropy should always be positive(>0).

8 0
3 years ago
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