Explain the difference between the 7 parts of the electromagnetic spectrum.

Physics

1 answer:

inn [45]3 years ago

3 0

Answer:

The difference between the two is, well for one

Spectrum: The entire range that the "waves" could be such, as visible light, x-ray's and so on.

Waves: These are different because they aren't telling you or showing the entire spectrum just which they length that they are.

It may confuse you but it makes sense to me (Sorry)

Explanation:

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An automobile of mass 1500kg moving at 25.0m/s collides with a truck of the mass 4500kg at rest. The car and the truck bounce of

Mekhanik [1.2K]

Answer: Both forces are equal each other.

Explanation:

If we assume that no external forces act during the collision (based on the fact that the collision time is very small), total momentum must be conserved, and Newton's 3rd law must apply.

If the total momentum is conserved, the change in momentum for the automobile (caused by the truck) must be equal to the one caused to the truck by the car.

This change in momentum is caused by internal forces, which must be equal each other (even though of opposite signs).

Another way to explain this, is that by Newton's 3rd Law, the force applied by the automobile to the car, must be equal and opposite to the one the truck is applying to the car at the same time.

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3 years ago

Which of the following diagrams accurately applies the Law of

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3 years ago

A closely wound circular coil has a radius of 6.00 cmand carries a current of 2.65 A. How many turns must it have if the magneti

ad-work [718]

Answer:

Given:

radius of the coil, R = 6 cm = 0.06 m

current in the coil, I = 2.65 A

Magnetic field at the center, B = $6.31\times 10^{4} T$

Solution:

To find the number of turns, N, we use the given formula:

$B = \frac{\mu_{o}NI}{2R}$

Therefore,

$N = \frac{2BR}{\mu_{o}I}$

$N = \frac{2\times 6.31\times 10^{4}\times 0.06}{4\pi \times 10^{- 7}\times 2.65}$

N = 22.74 = 23 turns (approx)

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If the velocity of a body changes from 13 m/s to 30 m/s while undergoing constant acceleration, what's the average velocity of t

Ronch [10]

Since the acceleration is constant, the average velocity is simply the average of the initial and final velocities of the body:

$v_{avg} = \frac{v_f+v_i}{2}=\frac{30 m/s+13 m/s}{2}=21.5 m/s$

We can proof that the distance covered by the body moving at constant average velocity $v_{avg}$ is equal to the distance covered by the body moving at constant acceleration a: