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3 years ago

Please help me! this is timed!

Physics

1 answer:

Arada [10]3 years ago

8 0

Answer:

Radiation

Explanation:

Radiation refers to the emission of energy in rays or waves

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A cannon is fired horizontally from atop a 40.0 m tower. The cannonball travels 175 m horizontally before it strikes the ground.

Anastasy [175]

The vertical movement of the projectile is described by:

y = H - gt² / 2

When the cannonball is on the ground, y= 0 so:

0 = H - gt² /2

Solving for t:

$t = \sqrt{\dfrac{2H}{g}} = \sqrt{\dfrac{2(40\;m)}{9.8\;m/s^2}} = 2.8\;s$

The horizontally movement of the projectile is described by:

x = v₀t

Solving for v₀:

v₀ = x/t

v₀ = 175 m / 2.8 s

v₀ = 61.5 m/s

3 0

3 years ago

when a substance such as ice melts, its temperature increases. desrcibe what happens to the arrangment of water molecules as the

trasher [3.6K]

Explanation:

The water molecules begins to leave their fixed position and begins to move as the temperature increases.

When ice melts, it undergoes a state change from solid to liquid and with increasing temperature becomes a gas.

The basis for this is the increasing movement of the molecules of the water as it transitions from one phase to another.
In the ice, the molecules are locked and fixed in the lattice
As the temperature increases, the average kinetic energy of the particles rises.
This makes the structure of the ice to collapse and forms liquids.
By the virtue of this, they flow and move over one another
With increasing temperature, the bonds are broken and vapor forms

7 0

3 years ago

Consider a steel guitar string of initial length L=1.00 meter and cross-sectional area A=0.500 square millimeters. The Young's m

Reil [10]

Answer:

$\Delta l=0.015m$

Explanation:

We have given initial length of the steel guitar l = 1 m

Cross sectional area $A=0.5mm^2=0.5\times 10^{-6}m^2$

Young's modulus $\gamma=2\times 10^{11}Pa$

Force F = 1500 N

So stress $=\frac{force}{area}=\frac{1500}{0.5\times 10^{-6}}=3000\times 10^{-6}=3\times 10^{9}Pa$

We know that young's modulus $=\frac{stress}{strain}$

So $2\times 10^{11}=\frac{3\times 10^{9}}{strain}$

$strain=1.5\times 10^{-2}=0.015m$

Now strain $=\frac{\Delta l}{l}$

$0.015=\frac{\Delta l}{1}$

$\Delta l=0.015m$

6 0

3 years ago

Read 2 more answers

In an elastic head-on collision, a 0.60 kg cart moving at 5.0 m/s [W] collides with a 0.80 kg cart moving at 2.0 m/s [E]. The co

labwork [276]

Answer:

The answer is given below

Explanation:

u is the initial velocity, v is the final velocity. Given that:

$m_1=0.6kg,u_1=-5m/s(moving \ west),m_2=0.8kg,u_2=2m/s,k=1200N/m$

The final velocity of cart 1 after collision is given as:

$v_1=(\frac{m_1-m_2}{m_1+m_2})u_1+\frac{2m_2}{m_1+m_2}u_2\\ Substituting:\\v_1=\frac{0.6-0.8}{0.6+0.8} (-5)+\frac{2*0.8}{0.6+0.8}(2)= 5/7+16/7=3\ m/s$

The final velocity of cart 2 after collision is given as:

$v_2=(\frac{m_2-m_1}{m_1+m_2})u_2+\frac{2m_1}{m_1+m_2}u_1\\ Substituting:\\v_1=\frac{0.8-0.6}{0.6+0.8} (2)+\frac{2*0.6}{0.6+0.8}(-5)= 2/7-30/7=-4\ m/s$

b) Using the law of conservation of energy:

$\frac{1}{2}m_1u_1+ \frac{1}{2}m_2u_2=\frac{1}{2}m_1v_1+\frac{1}{2}m_2v_2+\frac{1}{2}kx^2\\x=\sqrt{\frac{m_1u_1+m_2u_2-m_1v_1-m_2v_2}{k}}\\ Substituting\ gives:\\x=\sqrt{\frac{0.6*(-5)^2+0.8*2^2-(0.6*3^2)-(0.8*(-4)^2)}{1200}}=\sqrt{0}=0\ cm$

7 0

3 years ago

A force causes a mass of 4 kg to have an acceleration of 8 m/s2. Suppose something causes the mass to be one-quarter of its orig

solniwko [45]

Explanation:

From Newton's second law:

F = ma

Given that m = 4 kg and a = 8 m/s²:

F = (4 kg) (8 m/s²)

F = 32 N

If m is reduced to 1 kg and F stays at 32 N:

32 N = (1 kg) a

a = 32 m/s²

So the acceleration increases by a factor of 4.

5 0

3 years ago