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nikklg [1K]
3 years ago
10

Can someone please help me ASAP please!

Physics
1 answer:
natulia [17]3 years ago
8 0
It would be D (hoping the picture you posted is what you needed help with
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If a 1-megaton nuclear weapon is exploded
Elenna [48]

Answer:

1,780,000 N

Explanation:

0.2 atm × (1.013×10⁵ Pa/atm) = 20,260 Pa

Force = pressure × area

F = 20,260 Pa × (3.89 m × 22.6 m)

F = 1,780,000 N

4 0
2 years ago
A boy can swim 3.0 meter a second in still water while trying to swim directly across a river from west to east, he is pulled by
lana66690 [7]

Answer:

Angle: 48.19^o

Explanation:

<u>Two-Dimension Motion</u>

When the object is moving in one plane, the velocity, acceleration, and displacement are vectors. Apart from the magnitudes, we also need to find the direction, often expressed as an angle respect to some reference.

Our boy can swim at 3 m/s from west to east in still water and the river he's attempting to cross interacts with him at 2 m/s southwards. The boy will move east and south and will reach the other shore at a certain distance to the south from where he started. It happens because there is a vertical component of his velocity that is not compensated.

To compensate for the vertical component of the boy's speed, he only has to swim at a certain angle east of the north (respect to the shoreline). The goal is to make the boy's y component of his velocity equal to the velocity of the river. The vertical component of the boy's velocity is

v_b\ cos\alpha

where v_b is the speed of the boy in still water and \alpha is the angle respect to the shoreline. If the river flows at speed v_s, we now set

v_b\ cos\alpha=v_s

\displaystyle cos\alpha=\frac{v_s}{v_b}=\frac{2}{3}

\alpha=48.19^o

8 0
3 years ago
Tres móviles, A, B y C, con las mismas características tienen los siguientes estados: A se encuentra inicialmente en reposo y ca
Morgarella [4.7K]

Answer:

La respuesta es sí, hay una fuerza que actúa sobre el móvil A y es la única fuerza ya que A cae libremente bajo la influencia de la fuerza.

Explanation:

Según la primera ley de movimiento de Newton, un cuerpo continuará en su estado de reposo o en un movimiento uniforme en línea recta a menos que actúen sobre él fuerzas impresas.

Dado que el móvil A cae libremente, desde su estado de reposo inicial, según la primera ley de movimiento de Newton, experimenta una fuerza que actúa sobre él para hacer que caiga y continúe en caída libre.

El móvil B se mueve con una velocidad constante, por lo tanto, de acuerdo con la primera ley de movimiento de Newton, no hay fuerzas impresas que actúen sobre él.

El móvil C está completamente en reposo en el suelo, por lo tanto, tampoco hay fuerzas que actúen sobre él.

La respuesta es sí, hay una fuerza actuando sobre el móvil A y es la única fuerza cuando A cae libremente bajo la influencia de la fuerza.

6 0
4 years ago
Please help me to find out my mistake
Scrat [10]

From the calculation, the speed of sound at 10 K is 63.5 m/s.

<h3>What is the speed of sound?</h3>

We know that the speed of sound is directly proportional to the temperature of the body thus we can write;

V1/V2 = √T1/T2

Then;

T1 = 0 degrees or 273 K

T2 = 10 K

V1 = 330 m/s

V2 = ?

330/T2 = √273/10

330/T2 = 5.2

330 = 5.2T2

V2 = 330/5.2

V2 = 63.5 m/s

Learn more about speed of sound:brainly.com/question/15381147

#SPJ1

7 0
2 years ago
radio signals emitted from and received by an airplane have her fruit frequency of 3.00 * 10 to the 12th Hertz and travel at the
Elanso [62]

here we know that the speed of the signal is same as the speed of light

so here we will have

v = 3 \times 10^8 m/s

the altitude of the airplane is given as

h = 1 \times 10^4 m

now we know that time taken by the signal to reach the control tower is given as

t = \frac{d}{v}

now it is given as

t = \frac{1 \times 10^4 }{3 \times 10^8}

t = 3.33 \times 10^{-5} s

so above is the time taken by the signal to reach the control tower

3 0
3 years ago
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