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nata0808 [166]
2 years ago
15

The device or instrument that transforms light energy to electrical energy​

Physics
1 answer:
WINSTONCH [101]2 years ago
3 0

Answer:

Solar panels

sun light into electricity

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A 1kg mass is thrown to a height of 2cm. what is the potential energy​
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  • Mass=m=1kg
  • Height=h=2cm=0.02m
  • Acceleration due to gravity=g=10m/s^2

\\ \tt\hookrightarrow P.E=mgh

\\ \tt\hookrightarrow PE=1(10)(0.02)

\\ \tt\hookrightarrow PE=0.2J

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the maximum range of a projectile is 2÷√3 times its actual range what is the angle of the projection for the actual range​
Murrr4er [49]

Answer:

The actual angle is 30°

Explanation:

<h2>Equation of projectile:</h2><h2>y axis:</h2>

v_y(t)=vo*sin(A)-g*t

the velocity is Zero when the projectile reach in the maximum altitude:

0=vo-gt\\t=\frac{vo}{g}

When the time is vo/g the projectile are in the middle of the range.

<h2>x axis:</h2>

d_x(t)=vo*cos(A)*t\\

R=Range

R=d_x(t=2*\frac{vo}{g})

R=vo*cos(A)*2\frac{vo}{g} \\\\R=\frac{(vo)^{2}*2* sin(A)cos(A)}{g} \\\\R=\frac{(vo)^{2} sin(2A)}{g}

**sin(2A)=2sin(A)cos(A)

<h2>The maximum range occurs when A=45°(because sin(90°)=1)</h2><h2>The actual range R'=(2/√3)R:</h2>

Let B the actual angle of projectile

\frac{vo^{2} }{g} =(\frac{2}{\sqrt{3} }) \frac{vo^{2} *sin(2B)}{g}\\\\1= \frac{2 }{\sqrt{3}} *sin(2B)\\\\sin(2B)=\frac{\sqrt{3}}{2}\\\\

2B=60°

B=30°

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2 years ago
Which of the following statements best describes energy conservation in heat engines?
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B is the correct answer
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