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natali 33 [55]
3 years ago
8

A study group is meeting to prepare for an upcoming social studies test on the Civil War. Which question would you

Physics
2 answers:
Rainbow [258]3 years ago
4 0

Answer:

What were the most important reasons that the Civil War started?

Explanation: i got it correct

grin007 [14]3 years ago
3 0

Answer:

C.What were the most important reasons that the Civil War started?

Explanation:

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A motorcyclist changes the velocity of his bike from 20.0 meters/second to 35.0 meters/second under a constant acceleration of 4
Fiesta28 [93]
35-20 = 15m/s difference
15/4 = 3.75 seconds
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3 years ago
I need help on this one please
klio [65]

Lithium shares more properties with Sodium, because they have the same number of valence electrons (one). Choice 1 is correct. Hope this helps!

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3 years ago
Run Gizmo: Orbital velocity is the velocity needed to make a circular orbit. Use the Gizmo to find the orbital velocity of the b
Lina20 [59]

Answer:

Hmm i need more info

Explanation:

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3 years ago
Two rocks of different masses are rolling down a hill at the same speed. Which rock (small one or big one) would have more kinet
aivan3 [116]

Answer:

Kinetic energy of bigger rock will be more than that of smaller one.

Explanation:

Kinetic energy of the rock is given by,

Kinetic energy = \frac{1}{2} m v^{2}

As velocity of both the rocks are same. Thus, kinetic energy is directly proportional to the mass of the rock

Kinetic energy ∝ mass

So, For greater mass kinetic energy will be greater and for smaller mass kinetic energy will be smaller.

Hence, Kinetic energy of bigger rock will be more than that of smaller one.

3 0
3 years ago
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The force of attraction between two oppositely charged pith is 5mx 10 to the -6th power newtons. If the charge on the two is 6.7
My name is Ann [436]

Answer:

0.28 m

Explanation:

The following data were obtained from the question:

Force (F) = 5×10¯⁶ N

Charge 1 (q₁) = 6.7×10¯⁹ C

Charge 2 (q₂) = 6.7×10¯⁹ C

Electrical constant (K) = 9×10⁹ Nm²C¯²

Distance apart (r) =?

Thus, the distance between the two charges can be obtained as follow:

F = Kq₁q₂/r²

5×10¯⁶ = 9×10⁹ × 6.7×10¯⁹ × 6.7×10¯⁹/r²

5×10¯⁶ = 4.0401×10¯⁷ / r²

Cross multiply

5×10¯⁶ × r² = 4.0401×10¯⁷

Divide both side by 5×10¯⁶

r² = 4.0401×10¯⁷ / 5×10¯⁶

Take the square root of both side

r = √(4.0401×10¯⁷ / 5×10¯⁶)

r = 0.28 m

Therefore, the distance between the two charges is 0.28 m

4 0
3 years ago
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