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ololo11 [35]
4 years ago
8

These four surfaces are opaque; that is they reflect or absorb certain rays of light determine the color

Physics
1 answer:
masya89 [10]4 years ago
4 0
In the first figure, the surface absorbs all colors except for green light, which is reflected: so, the surface will appear as green to our eyes, because green is the only color which is reflected by that surface.

Similarly, in the  second figure, the surface absorbs all colors except for blue, and so the surface will appear blue to our eyes.

In the third figure, the surface absorbs all colors, so it will appear black to our eyes (because no colors are reflected, and black=absence of colors).

In the fourth figure, all colors are reflected: this means the surface will appear white to our eyes (white= sum of all colors).
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A car is traveling at 26.0 m/s when the driver suddenly applies the brakes, causing the car to slow down with constant accelerat
UkoKoshka [18]

Answer:

a = -2.82 m/s²

v = 18.4 m/s

Explanation:

Initial velocity, u = 26.0 m/s

Final velocity, v = 0 m/s

Distance travelled, s = 120m

Using

v² = u² + 2as

0 = 26² + 2(120)a

a= -2.82 m/s²

Velocity of the car when it was 60.0m past the point where the brakes were applied:

u = 26.0 m/s

a = -2.82 m/s²

s = 60m

Using

v² = u² + 2as

v² = 26² + 2(-2.82)(60)

v² = 337.6

v = 18.4 m/s

5 0
3 years ago
ifif it takes 1-minute for 45 c of charge to pass a point in an electric circuit what is the current through the circuit?​
Rudiy27

Answer:

45C in a minute is

45/60 C in a second

.75 C in a second is 3/4 of an ampere.

Explanation:

5 0
3 years ago
Lucinda frequently finds herself getting upset and yelling at her husband, co-workers, and friends. What therapeutic technique w
IrinaK [193]

The therapeutic technique Lucinda would start is behavioral self-monitoring.

<u>Explanation:</u>

Behavioral self-monitoring, introduced by Mark Snyder in the 1970s, is an ability of an individual to regulate the behavior to accommodate in various social situations.

Here, Lucinda frequently gets upset and yells at her husband, co-workers, and friends. She wants to keep a record of where, when, or with whom she might lose her temper in order to evaluate her behavior.

The individuals with high levels of self-monitoring possess greater skill at bridging social situations and in relationships they seem to be more flexible and adaptable.

6 0
4 years ago
A roller skater of 47kg moving with a velocity of 12 m/s to the east picks up a bag of 6.0 kg. What is the final velocity of the
WITCHER [35]

Answer:

v_f = 10.85 m/s

Explanation:

We will apply the law of conservation of momentum here:

m_{1}v_{1i} + m_{2}v_{2i} = m_{1}v_{1f}+m_{2}v_{2f}\\

where,

m₁ = mass of roller skater = 47 kg

m₂ = mass of bag = 6 kg

v_1i = initial speed of roller skater = 12 m/s

v_2i = initial speed of the bag = 0 m/s

v_1f = final speed of the roller skater = ?

v_2f = final speed of the bag = ?

Both the bag and the skater will have same speed at the end because kater is carrying the bag:

v_1f = v_2f = v_f

Therefore, the equation will become:

(47\ kg)(12\ m/s)+(6\ kg)(0\ m/s)=(47\ kg)(v_{f})+(5\ kg)(v_{f})\\564\ N.s = (47\ kg+5\ kg)(v_{f})\\v_{f} = \frac{564\ N.s}{52\ kg}\\

<u>v_f = 10.85 m/s</u>

8 0
3 years ago
You're driving down the highway late one night at 20 m/s when a deer steps onto the road 49 m in front of you. You reaction time
Leno4ka [110]

Answer:

v = 26.7 m/s

Explanation:

Given,

speed of the car = 20 m/s

distance between the car and the deer = 49 m

time taken to press the brake = 0.50 s

maximum deceleration of the car = 10 m/s²

Now,

distance travel by the car in 0.5 s = u x t = 20 x 0.5 = 10 m

distance travel by the car after the break is pressed

Using equation of motion

v² = u² + 2 a s

0² = 20² - 2 x 10 x s

s = 20 m

Total distance travel by the car = 20 + 10 = 30 m

Distance between deer and car = 49-30 = 19 m.

b. Maximum speed a car could have

Distance travel by the car in reaction time = v' x 0.5

v' is the maximum speed of the car.

maximum distance car can cover = 49 - 0.5 v'

Now, Using equation of motion

v² = u² + 2 a s

0² =v'² - 2 x 10 x (49- 0.5 x v')

v'² +10 v' -980 = 0

By solving

v = 26.7 m/s

Hence, maximum speed of the car can be 26.7 m/s

 

4 0
4 years ago
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