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Ksju [112]
3 years ago
5

Three equal point charges, each with charge 1.25 μC , are placed at the vertices of an equilateral triangle whose sides are of l

ength 0.450 m . What is the electric potential energy U of the system
Physics
1 answer:
natali 33 [55]3 years ago
7 0

Answer:

electric potential energy  is 9.36 ×10^{-2} J

Explanation:

given data

charge q = 1.25 μC =1.25×10^{-6} C

length L = 0.450 m

to find out

electric potential energy

solution

we apply electric potential energy U formula

U = U1 + U2 + U3   .................1

we know magnitude of all three charge is

q = q1 = q2 = q3

so here from 1

U = 1 / 4π∈ × (q²/L + q²/L +q²/L )

U = 1 / 4π∈ × 3(q²/L)

put here all value and we know ∈ = 8.85 ×10^{-12} F/m

U = 1 / 4π( 8.85 ×10^{-12}) × ( 3 (1.25×10^{-6})² / 0.450 )

U = 8.99×10^{9} × ( 3 (1.25×10^{-6})² / 0.450 )

U = 9.36 ×10^{-2}

so electric potential energy  is 9.36 ×10^{-2} J

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